Physics-
General
Easy

Question

An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially un stretched. Then the maximum extension in the spring is

  1. 4 Mg/K    
  2. 2 Mg/K    
  3. Mg/K    
  4. Mg/2K    

The correct answer is: 2 Mg/K


    Let x be the maximum extension of the spring. From energy conservation
    Loss in gravitational potential energy
    = Gain in potential energy of spring
    M g x equals fraction numerator 1 over denominator 2 end fraction K x to the power of 2 end exponent
    rightwards double arrow x equals fraction numerator 2 M g over denominator K end fraction

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