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Physics-

General

Easy

Question

At which place, earth's magnetism become horizontal

Magnetic pole
Geographical pole
Magnetic meridian
Magnetic equator

The correct answer is: Magnetic equator

At equator angle of dip is zero.

Related Questions to study

At a certain place the horizontal component of the earth’s magnetic field is B₀ and the angle of dip is 45^o. The total intensity of the field at that place will be

At a certain place the horizontal component of the earth’s magnetic field is B₀ and the angle of dip is 45^o. The total intensity of the field at that place will be

Physics-General

At a certain place, the horizontal component $B subscript 0 end subscript$ and the vertical component $V subscript 0 end subscript$ of the earth's magnetic field are equal in magnitude. The total intensity at the place will be

At a certain place, the horizontal component $B subscript 0 end subscript$ and the vertical component $V subscript 0 end subscript$ of the earth's magnetic field are equal in magnitude. The total intensity at the place will be

Physics-General

Lines which represent places of constant angle of dip are called

Lines which represent places of constant angle of dip are called

Physics-General

parallel

At a place, the horizontal and vertical intensities of earth's magnetic field is 0.30 Gauss and 0.173 Gauss respectively. The angle of dip at this place is

At a place, the horizontal and vertical intensities of earth's magnetic field is 0.30 Gauss and 0.173 Gauss respectively. The angle of dip at this place is

Physics-General

The angle of dip is the angle

The angle of dip is the angle

Physics-General

If the normal at the points P_i (x_i, y_i), i = 1 to 4 on the hyperbola xy = c² are concurrent at the point Q(h, k), then $fraction numerator open parentheses x subscript 1 end subscript plus x subscript 2 end subscript plus x subscript 3 end subscript plus x subscript 4 end subscript close parentheses open parentheses y subscript 1 end subscript plus y subscript 2 end subscript plus y subscript 3 end subscript plus y subscript 4 end subscript close parentheses over denominator x subscript 1 end subscript x subscript 2 end subscript x subscript 3 end subscript x subscript 4 end subscript end fraction$ is equal to

If the normal at the points P_i (x_i, y_i), i = 1 to 4 on the hyperbola xy = c² are concurrent at the point Q(h, k), then $fraction numerator open parentheses x subscript 1 end subscript plus x subscript 2 end subscript plus x subscript 3 end subscript plus x subscript 4 end subscript close parentheses open parentheses y subscript 1 end subscript plus y subscript 2 end subscript plus y subscript 3 end subscript plus y subscript 4 end subscript close parentheses over denominator x subscript 1 end subscript x subscript 2 end subscript x subscript 3 end subscript x subscript 4 end subscript end fraction$ is equal to

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The most general form of the equation of a conic is given by $a x to the power of 2 end exponent plus 2 h x y plus b y to the power of 2 end exponent plus 2 f y equals 0$ . Let x and y-axes be respectively tangent and normal to the conic given by equation ((a) at the origin. Then clearly c = 0. Also by putting y = 0, we get $a x to the power of 2 end exponent plus 2 g x$ = 0. Both roots of the equation are zero. Therefore g = 0.
Hence the most general form of the equation of such a conic is given by $blank a x to the power of 2 end exponent plus 2 h x y plus b y to the power of 2 end exponent plus 2 f y equals 0$ .
Let foci of the conic represented by the equation $blank a x to the power of 2 end exponent plus 2 left parenthesis a plus 2 right parenthesis x y plus a y to the power of 2 end exponent plus 2 f y equals 0$ , where $a less than negative 1$ and $f not equal to 0$ be $F subscript 1 end subscript left parenthesis 2 comma negative 3 right parenthesis blank$ and $blank F subscript 2 end subscript left parenthesis 8 comma negative 5 right parenthesis$ . Then the feet of perpendiculars from F₁ and F₂ upon x-axis lie on the curve

The most general form of the equation of a conic is given by $a x to the power of 2 end exponent plus 2 h x y plus b y to the power of 2 end exponent plus 2 f y equals 0$ . Let x and y-axes be respectively tangent and normal to the conic given by equation ((a) at the origin. Then clearly c = 0. Also by putting y = 0, we get $a x to the power of 2 end exponent plus 2 g x$ = 0. Both roots of the equation are zero. Therefore g = 0.
Hence the most general form of the equation of such a conic is given by $blank a x to the power of 2 end exponent plus 2 h x y plus b y to the power of 2 end exponent plus 2 f y equals 0$ .
Let foci of the conic represented by the equation $blank a x to the power of 2 end exponent plus 2 left parenthesis a plus 2 right parenthesis x y plus a y to the power of 2 end exponent plus 2 f y equals 0$ , where $a less than negative 1$ and $f not equal to 0$ be $F subscript 1 end subscript left parenthesis 2 comma negative 3 right parenthesis blank$ and $blank F subscript 2 end subscript left parenthesis 8 comma negative 5 right parenthesis$ . Then the feet of perpendiculars from F₁ and F₂ upon x-axis lie on the curve

According to Huckel’s rule a compound is said to be aromatic if it contains

According to Huckel’s rule a compound is said to be aromatic if it contains

Chemistry-General

structure is

structure is

Chemistry-General

parallel

Two volatile liquids A and B differ in their boiling points by 0 15 C The process which can be used to separate them is

Two volatile liquids A and B differ in their boiling points by 0 15 C The process which can be used to separate them is

Chemistry-General

Consider the ellipse whose equation is $fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1$ For certain pair of diameters of the above ellipse, the product of their slopes is equal to $negative fraction numerator b to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction$
The equations of two diameters are $y equals x$ and $3 y equals negative 2 x$ satisfying the condition mentioned above. Then the eccentricity of the ellipse is

Consider the ellipse whose equation is $fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1$ For certain pair of diameters of the above ellipse, the product of their slopes is equal to $negative fraction numerator b to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction$
The equations of two diameters are $y equals x$ and $3 y equals negative 2 x$ satisfying the condition mentioned above. Then the eccentricity of the ellipse is

The smallest possible value of S $equals a subscript 1 end subscript times a subscript 2 end subscript times a subscript 3 end subscript plus b subscript 1 end subscript times b subscript 2 end subscript times b subscript 3 end subscript plus c subscript 1 end subscript times c subscript 2 end subscript times c subscript 3 end subscript text end text$ where $text end text a subscript 1 end subscript comma a subscript 2 end subscript comma a subscript 3 end subscript comma b subscript 1 end subscript comma b subscript 2 end subscript comma b subscript 3 end subscript comma c subscript 1 end subscript comma c subscript 2 end subscript comma c subscript 3 end subscript$ is a permutation of the number 1, 2, 3, 4, 5, 6, 7, 8, and 9 is

The smallest possible value of S $equals a subscript 1 end subscript times a subscript 2 end subscript times a subscript 3 end subscript plus b subscript 1 end subscript times b subscript 2 end subscript times b subscript 3 end subscript plus c subscript 1 end subscript times c subscript 2 end subscript times c subscript 3 end subscript text end text$ where $text end text a subscript 1 end subscript comma a subscript 2 end subscript comma a subscript 3 end subscript comma b subscript 1 end subscript comma b subscript 2 end subscript comma b subscript 3 end subscript comma c subscript 1 end subscript comma c subscript 2 end subscript comma c subscript 3 end subscript$ is a permutation of the number 1, 2, 3, 4, 5, 6, 7, 8, and 9 is

parallel

Statement 1 : The second degree equation $4 x to the power of 2 end exponent plus 9 y to the power of 2 end exponent minus 24 x plus 36 y minus 72 equals 0$ represents an ellipse Because
Statement 2 : $a x to the power of 2 end exponent plus 2 h x y plus b y to the power of 2 end exponent plus 2 g x plus 2 f y plus c equals 0$ represents an ellipse if $capital delta equals a b c plus 2 f g h minus a f to the power of 2 end exponent minus b g to the power of 2 end exponent minus c h to the power of 2 end exponent not equal to 0$ and $h to the power of 2 end exponent greater than a b$

Statement 1 : The second degree equation $4 x to the power of 2 end exponent plus 9 y to the power of 2 end exponent minus 24 x plus 36 y minus 72 equals 0$ represents an ellipse Because
Statement 2 : $a x to the power of 2 end exponent plus 2 h x y plus b y to the power of 2 end exponent plus 2 g x plus 2 f y plus c equals 0$ represents an ellipse if $capital delta equals a b c plus 2 f g h minus a f to the power of 2 end exponent minus b g to the power of 2 end exponent minus c h to the power of 2 end exponent not equal to 0$ and $h to the power of 2 end exponent greater than a b$

Statement-1: P is any point such that the chord of contact of tangents from P to the ellipse $x to the power of 2 end exponent plus 2 y to the power of 2 end exponent equals 6$ touches $x to the power of 2 end exponent plus 4 y to the power of 2 end exponent equals 4$ The the tangents from P of $x to the power of 2 end exponent plus 2 y to the power of 2 end exponent equals 6$ are at right angles and
Statement-2: The tangent from any point on the director circle of an ellipse are at right angles

Statement-1: P is any point such that the chord of contact of tangents from P to the ellipse $x to the power of 2 end exponent plus 2 y to the power of 2 end exponent equals 6$ touches $x to the power of 2 end exponent plus 4 y to the power of 2 end exponent equals 4$ The the tangents from P of $x to the power of 2 end exponent plus 2 y to the power of 2 end exponent equals 6$ are at right angles and
Statement-2: The tangent from any point on the director circle of an ellipse are at right angles

Statement-1: The distance of the tangent through (0, (d) from a focus of the ellipse $fraction numerator x to the power of 2 end exponent over denominator 16 end fraction plus fraction numerator y to the power of 2 end exponent over denominator 7 end fraction equals 1$ is 5
and
Statement-2: The locus of the foot of the perpendicular from a focus on any tangent to $fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1$ is $x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent$

Statement-1: The distance of the tangent through (0, (d) from a focus of the ellipse $fraction numerator x to the power of 2 end exponent over denominator 16 end fraction plus fraction numerator y to the power of 2 end exponent over denominator 7 end fraction equals 1$ is 5
and
Statement-2: The locus of the foot of the perpendicular from a focus on any tangent to $fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1$ is $x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent$

parallel

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