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Physics-

General

Easy

Question

For a particle in uniform circular motion, thee acceleration $stack a with rightwards arrow on top$ at a point $P left parenthesis R comma theta right parenthesis$ on the circle of radius R is (Here $theta$ is measured from the x-axis)

$\frac{v^{2}}{R} \hat{i} + \frac{v^{2}}{R} \hat{j}$
$- \frac{v^{2}}{R} \cos θ \hat{i} + \frac{v^{2}}{R} \sin θ \hat{j}$
$- \frac{v^{2}}{R} \sin θ \hat{i} + \frac{v^{2}}{R} \cos θ \hat{j}$
$- \frac{v^{2}}{R} \cos θ \hat{i} - \frac{v^{2}}{R} \sin θ \hat{j}$

The correct answer is: $negative fraction numerator v to the power of 2 end exponent over denominator R end fraction cos invisible function application theta stack i with hat on top minus fraction numerator v to the power of 2 end exponent over denominator R end fraction sin invisible function application theta stack j with hat on top$

$stack a with rightwards arrow on top equals negative fraction numerator v to the power of 2 end exponent over denominator R end fraction cos invisible function application theta stack i with hat on top minus fraction numerator v to the power of 2 end exponent over denominator R end fraction sin invisible function application theta stack j with hat on top$

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