Physics-
General
Easy

Question

If a cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration of a point on the cycle wheel will be

  1. pi to the power of 2 end exponent m divided by s to the power of 2 end exponent  
  2. 2 pi to the power of 2 end exponent m divided by s to the power of 2 end exponent  
  3. 4 pi to the power of 2 end exponent m divided by s to the power of 2 end exponent  
  4. 8 pi m divided by s to the power of 2 end exponent  

The correct answer is: 4 pi to the power of 2 end exponent m divided by s to the power of 2 end exponent


    Centripetal acceleration equals 4 pi to the power of 2 end exponent n to the power of 2 end exponent r equals 4 pi to the power of 2 end exponent open parentheses fraction numerator 1 over denominator 2 end fraction close parentheses to the power of 2 end exponent cross times 4 equals 4 pi to the power of 2 end exponent

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