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Physics

Mechanics

Easy

Question

Four point size bodies each of mass m are fixed at four corners of light square frame of side length 1m. The radius of gyration of these four bodies about an axis perpendicular to the plane of frame passing through its centre is

$\sqrt{2}$
2
$\frac{1}{\sqrt{2}}$
$\frac{1}{2}$

The correct answer is: $fraction numerator 1 over denominator square root of 2 end fraction$

$I equals 2 m l squared semicolon space k equals square root of fraction numerator I over denominator 4 m end fraction end root$

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