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Physics-

General

Easy

Question

Two bodies are thrown up at angles of $45 degree$ and $60 degree$ , respectively with the horizontal. If both bodies attain same vertical height , then the ratio of velocities with which these are thrown is

$\sqrt{\frac{2}{3}}$
$\frac{2}{\sqrt{3}}$
$\sqrt{\frac{3}{2}}$
$\frac{\sqrt{3}}{2}$

The correct answer is: $square root of fraction numerator 3 over denominator 2 end fraction end root$

$H subscript m a x end subscript equals fraction numerator u to the power of 2 end exponent sin to the power of 2 end exponent invisible function application theta over denominator 2 g end fraction$
According to problem $fraction numerator u subscript 1 end subscript superscript 2 end superscript sin to the power of 2 end exponent invisible function application 45 degree over denominator 2 g end fraction equals fraction numerator u subscript 2 end subscript superscript 2 end superscript sin to the power of 2 end exponent invisible function application 60 degree over denominator 2 g end fraction$
$rightwards double arrow fraction numerator u subscript 1 end subscript superscript 2 end superscript over denominator u subscript 2 end subscript superscript 2 end superscript end fraction equals fraction numerator sin to the power of 2 end exponent invisible function application 60 degree over denominator sin to the power of 2 end exponent invisible function application 30 degree end fraction rightwards double arrow fraction numerator u subscript 1 end subscript over denominator u subscript 2 end subscript end fraction equals fraction numerator square root of 3 divided by 2 over denominator 1 divided by square root of 2 end fraction equals square root of fraction numerator 3 over denominator 2 end fraction end root$

Related Questions to study

A helicopter is flying horizontally at an altitude of 2 km with a speed of $100 blank m s to the power of negative 1 end exponent$ . A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is $left parenthesis g equals 10 blank m s to the power of negative 2 end exponent right parenthesis$

A helicopter is flying horizontally at an altitude of 2 km with a speed of $100 blank m s to the power of negative 1 end exponent$ . A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is $left parenthesis g equals 10 blank m s to the power of negative 2 end exponent right parenthesis$

Physics-General

If the sides be a, b, c then $fraction numerator b minus c over denominator r subscript 1 end subscript end fraction$ + $fraction numerator c minus a over denominator r subscript 2 end subscript end fraction$ + $fraction numerator a minus b over denominator r subscript 3 end subscript end fraction$ =

If the sides be a, b, c then $fraction numerator b minus c over denominator r subscript 1 end subscript end fraction$ + $fraction numerator c minus a over denominator r subscript 2 end subscript end fraction$ + $fraction numerator a minus b over denominator r subscript 3 end subscript end fraction$ =

If the sides be a, b, c then (r + r1) tan $fraction numerator B minus C over denominator 2 end fraction$ + (r + r2) tan $fraction numerator C minus A over denominator 2 end fraction$ + (r+ r3) tan $fraction numerator A minus B over denominator 2 end fraction$ =

If the sides be a, b, c then (r + r1) tan $fraction numerator B minus C over denominator 2 end fraction$ + (r + r2) tan $fraction numerator C minus A over denominator 2 end fraction$ + (r+ r3) tan $fraction numerator A minus B over denominator 2 end fraction$ =

parallel

$open parentheses fraction numerator 1 over denominator r subscript 1 end subscript end fraction plus fraction numerator 1 over denominator r subscript 2 end subscript end fraction close parentheses$ $open parentheses fraction numerator 1 over denominator r subscript 3 end subscript end fraction plus fraction numerator 1 over denominator r subscript 1 end subscript end fraction close parentheses$ =

$open parentheses fraction numerator 1 over denominator r subscript 1 end subscript end fraction plus fraction numerator 1 over denominator r subscript 2 end subscript end fraction close parentheses$ $open parentheses fraction numerator 1 over denominator r subscript 3 end subscript end fraction plus fraction numerator 1 over denominator r subscript 1 end subscript end fraction close parentheses$ =

(r1 – r) (r2 – r) (r3 – r) =

(r1 – r) (r2 – r) (r3 – r) =

$fraction numerator 1 over denominator r subscript 1 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 2 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 3 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript blank superscript 2 end superscript end fraction$ =

$fraction numerator 1 over denominator r subscript 1 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 2 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 3 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript blank superscript 2 end superscript end fraction$ =

parallel

If (a – b) (s – c) = (b – c) (s – a) then r1, r2, r3 are in -

If (a – b) (s – c) = (b – c) (s – a) then r1, r2, r3 are in -

If in a triangle $open parentheses 1 minus fraction numerator r subscript 1 end subscript over denominator r subscript 3 end subscript end fraction close parentheses$ = 2, then the triangle is-

If in a triangle $open parentheses 1 minus fraction numerator r subscript 1 end subscript over denominator r subscript 3 end subscript end fraction close parentheses$ = 2, then the triangle is-

The angles of a right-angled triangle are in A.P. The ratio of the in-radius and the perimeter is -

The angles of a right-angled triangle are in A.P. The ratio of the in-radius and the perimeter is -

parallel

In a ABC, if $fraction numerator R over denominator r end fraction$  2, then the triangle is -

In a ABC, if $fraction numerator R over denominator r end fraction$  2, then the triangle is -

abc =

abc =

If the altitudes of a triangle be 3, 4, 6 then its in-radius is -

If the altitudes of a triangle be 3, 4, 6 then its in-radius is -

parallel

4Rr cos $fraction numerator A over denominator 2 end fraction$ cos $fraction numerator B over denominator 2 end fraction$ cos $fraction numerator C over denominator 2 end fraction$ =

4Rr cos $fraction numerator A over denominator 2 end fraction$ cos $fraction numerator B over denominator 2 end fraction$ cos $fraction numerator C over denominator 2 end fraction$ =

If the area of a triangle is 81 square cm and its perimeter is 27cm then its in-radius in centi-metres is -

If the area of a triangle is 81 square cm and its perimeter is 27cm then its in-radius in centi-metres is -

(r1 + r2) (r2 + r3) (r3 + r1) =

(r1 + r2) (r2 + r3) (r3 + r1) =

parallel

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