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Physics-

General

Easy

Question

A tangent galvanometer has a coil of 25 turns and radius of 15 cm. The horizontal component of the earth’s magnetic field is 3 ´ 10^–5 T. The current required to produce a deflection of 45^o in it, is

0.29 A
1.2 A
3.6 ' 10^–5 A
0.14 A

The correct answer is: 0.29 A

$i equals fraction numerator 2 r B subscript H end subscript over denominator mu subscript 0 end subscript N end fraction tan invisible function application theta$
$rightwards double arrow i equals fraction numerator 2 cross times 15 cross times 1 0 to the power of negative 2 end exponent cross times 3 cross times 1 0 to the power of negative 5 end exponent over denominator 4 pi cross times 1 0 to the power of negative 7 end exponent cross times 25 end fraction cross times tan invisible function application 4 5 to the power of o end exponent rightwards double arrow i equals 0.29 A$

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