Physics
Grade-9
Easy
Question
Two wires of the same material have the same length, but their radii are in the ratio of 5:3. They are combined in series, where the resistance of the thicker wire is 12 ohms. Calculate the total resistance of the combination
- 40 Ω
- 12 Ω
- 33.3 Ω
- 0.03 Ω
Hint:
The total resistance of the combination of resistors in series is RT= R1+R2
The correct answer is: 33.3 Ω
When two wires of radii in the ratio of 5:3 are combined in series, where the resistance of the thicker wire is 12 ohms, the resistance of the combination is 32 Ω.
- Given, the radii of the wire are in the ratio of 5:3 which is R2/R1
- We can write it as, R2/R1= 5/3, where R2= (5/3) R1
- The R1 given is the thicker wire with resistance of 12 Ω. So R2=
- Hence, their total resistance is RT= R1+R2, i.e. 12+20= 32 Ω
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