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Question

A student says that the expansion of the expression left parenthesis negative 4 y plus z right parenthesis to the power of 7has seven terms. Describe and correct
the error the student may have made ?

The correct answer is: Thus, we get 8 terms in the expansion. The student may have considered n=6 to get an expansion of 7 terms.


    ANSWER:
    Hint:
    The expansion of the expression left parenthesis x plus y right parenthesis to the power of n would have n+1 terms. The binomial expansion is left parenthesis x plus y right parenthesis to the power of n equals sum from k equals 0 to n of   n C subscript k x to the power of n minus k end exponent y to the power of k, here .
    We are asked to describe and correct the error the student has made while expanding left parenthesis negative 4 y plus z right parenthesis to the power of 7and getting only seven terms.
    Step 1 of 2:
    The given expression is left parenthesis negative 4 y plus z right parenthesis to the power of 7 . Here, the values of x equals negative 4 y straight & y equals z. The value of n=7.
    Step 2 of 2:
    Substitute the values in the binomial expansion to get the terms:
    left parenthesis negative 4 y plus z right parenthesis to the power of 7 equals 7 C subscript 0 left parenthesis negative 4 y right parenthesis to the power of 7 plus 7 C subscript 1 left parenthesis negative 4 y right parenthesis to the power of 6 left parenthesis z right parenthesis plus 7 C subscript 2 left parenthesis negative 4 y right parenthesis to the power of 5 left parenthesis z right parenthesis squared plus 7 C subscript 3 left parenthesis negative 4 y right parenthesis to the power of 4 left parenthesis z right parenthesis cubed plus
    7 C subscript 4 left parenthesis negative 4 y right parenthesis cubed left parenthesis z right parenthesis to the power of 4 plus 7 C subscript 5 left parenthesis negative 4 y right parenthesis squared left parenthesis z right parenthesis to the power of 5 plus 7 C subscript 6 left parenthesis negative 4 y right parenthesis left parenthesis z right parenthesis to the power of 6 plus 7 C subscript 7 left parenthesis z right parenthesis to the power of 7
    equals 1 open parentheses negative 16384 y to the power of 7 close parentheses plus 7 open parentheses 4096 y to the power of 6 close parentheses left parenthesis z right parenthesis plus 21 open parentheses negative 1024 y to the power of 5 close parentheses left parenthesis z right parenthesis squared plus 35 open parentheses 256 y to the power of 4 close parentheses left parenthesis z right parenthesis cubed plus
    35 open parentheses negative 64 y cubed close parentheses left parenthesis z right parenthesis to the power of 4 plus 21 open parentheses 16 y squared close parentheses left parenthesis z right parenthesis to the power of 5 plus 7 left parenthesis negative 4 y right parenthesis left parenthesis z right parenthesis to the power of 6 plus z to the power of 7equals negative 16384 y to the power of 7 plus 28672 y to the power of 6 z minus 21504 y to the power of 5 z squared plus 8960 y to the power of 4 z cubed minus 2240 y cubed z to the power of 4 plus 336 y squared z to the power of 5 minus 28 y z to the power of 6 plus z to the power of 7
    Thus, we get 8 terms in the expansion. The student may have considered n=6 to get an expansion of 7 terms.
    Note:
    The answer can be found the Pascal’s triangle as well. The expansion of an expression left parenthesis x plus y right parenthesis to the power of n has n+ 1 term.

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