Maths-
General
Easy

Question

A table of values for the quadratic function g is shown, Do the graphs of the functions g and f(x)= 3(x-1)2 +2 have the same axis of symmetry? Explain.

hintHint:

The vertex form of a quadratic function is
f(x) = a(x – h)2 + k
Where a, h, and k are constants. Here, h represents horizontal translation, a represents vertical translation and (h,k) is the vertex of the parabola. Also, a represents the Vertical stretch/shrink of the parabola and if a is negative, then the graph is reflected over the x-axis.
The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola. The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.
 

The correct answer is: Hence, the functions g(x) and f(x) do not have the same axis of symmetry


    Given, f(x) =3(x-1)2 +2
    Here, h = 1, k = 2.
    So, the vertex of the parabola is (1,2) and the axis of the symmetry is x = 1
    Now, let’s find the function g(x). Let’s say g(x) = a(x – h)2 + k
    Put x = -4 and g(x) = 8
    8 = a(-4-h)2 + k
    8 = a(16 + h2 + 8h) + k
    8 = 16a + ah2 + 8ah + k …….(1)
    Put x = -2 and g(x) = 3
    3 = a(-2-h)2 + k
    3 = a(4 + h2 + 4h) + k
    3 = 4a + ah2 + 4ah + k …….(2)
    Put x = 0 and g(x) = 0
    0 = a(0-h)2 + k
    0 = ah2 + k
    k = - ah2     …….(3)
    Put k = -ah2 in equation 1
    16a + ah2 + 8ah - ah2 = 8
    16 a + 8 ah = 8
    a =  fraction numerator 1 over denominator 2 plus h end fraction   ……(4)
    Put k = -ah2 and a =  in equation 2
    4fraction numerator 1 over denominator 2 plus h end fraction + ah2 + 4fraction numerator 1 over denominator 2 plus h end fractionh - ah2 = 3
    4fraction numerator 1 over denominator 2 plus h end fraction + 4fraction numerator 1 over denominator 2 plus h end fractionh = 3
    fraction numerator 4 plus 4 h over denominator 2 plus h end fraction equals 3
    4 + 4h = 6 + 3h
    h = 2
    Put h = 2 in equation 4
    a = 1 fourth
    Put h = 2 and a = 1 fourth in equation 3
    k = - 1 fourth × 22 = -1
    So, a = 1 fourth, h = 2 and k = -1.
    So, g(x) = (x – 2)2 - 1
    Here, h = 2, k = -1.
    So, the vertex of the parabola is (2,-1) and the axis of the symmetry is x = 2
    Final Answer:
    Hence, the functions g(x) and f(x) do not have the same axis of symmetry.

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