Maths-
General
Easy
Question
A table of values for the quadratic function g is shown, Do the graphs of the functions g and f(x)= 3(x-1)2 +2 have the same axis of symmetry? Explain.
Hint:
The vertex form of a quadratic function is
f(x) = a(x – h)2 + k
Where a, h, and k are constants. Here, h represents horizontal translation, a represents vertical translation and (h,k) is the vertex of the parabola. Also, a represents the Vertical stretch/shrink of the parabola and if a is negative, then the graph is reflected over the x-axis.
The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola. The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.
The correct answer is: Hence, the functions g(x) and f(x) do not have the same axis of symmetry
Given, f(x) =3(x-1)2 +2
Here, h = 1, k = 2.
So, the vertex of the parabola is (1,2) and the axis of the symmetry is x = 1
Now, let’s find the function g(x). Let’s say g(x) = a(x – h)2 + k
Put x = -4 and g(x) = 8
8 = a(-4-h)2 + k
8 = a(16 + h2 + 8h) + k
8 = 16a + ah2 + 8ah + k …….(1)
Put x = -2 and g(x) = 3
3 = a(-2-h)2 + k
3 = a(4 + h2 + 4h) + k
3 = 4a + ah2 + 4ah + k …….(2)
Put x = 0 and g(x) = 0
0 = a(0-h)2 + k
0 = ah2 + k
k = - ah2 …….(3)
Put k = -ah2 in equation 1
16a + ah2 + 8ah - ah2 = 8
16 a + 8 ah = 8
a = ……(4)
Put k = -ah2 and a = in equation 2
4 + ah2 + 4h - ah2 = 3
4 + 4h = 3
4 + 4h = 6 + 3h
h = 2
Put h = 2 in equation 4
a =
Put h = 2 and a = in equation 3
k = - × 22 = -1
So, a = , h = 2 and k = -1.
So, g(x) = (x – 2)2 - 1
Here, h = 2, k = -1.
So, the vertex of the parabola is (2,-1) and the axis of the symmetry is x = 2
Final Answer:
Hence, the functions g(x) and f(x) do not have the same axis of symmetry.
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