Maths-
General
Easy
Question
A man goes 10 m due east and then 30 m in due north. Find the distance from the starting place.
Hint:
Pythagoras' theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°.
If a is the perpendicular, b is the base, and c is the hypotenuse, then according to the definition, the Pythagoras Theorem formula is given as
c2= a2 + b2
The correct answer is: Hence, the distance from the starting point is 10√10 m
Here, Length of perpendicular(a) = 30 m
Length of base(b) = 10 m
Let’s say that the distance from the starting point is given as d and here that distance is the hypotenuse of the right-angled triangle.
Using Pythagoras theorem
d2 = a2 + b2
d2 = 302 + 102
d2 = 1000
Final Answer:
Hence, the distance from the starting point is 10 
m
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