Maths-
General
Easy
Question
Sarah said the vertex of the function f(x)= (x+2)2+6 is (2,6). Is she correct, Explain your answer.
Hint:
The vertex form of a quadratic function is
f(x) = a(x – h)2 + k
Where a, h, and k are constants. Here, h represents horizontal translation, a represents vertical translation and (h,k) is the vertex of the parabola. Also, a represents the Vertical stretch/shrink of the parabola and if a is negative, then the graph is reflected over the x-axis.
The correct answer is: Hence, the vertex given by Sarah is wrong
Given f(x)= (x+2)2+6 = (x-(-2))2+6
Here, h = -2 and k = 6
So, the vertex of the graph is (-2,6)
The vertex given by Sarah is (2,6) which is wrong.
Final Answer:
Hence, the vertex given by Sarah is wrong.
Related Questions to study
Maths-
Solve Graphically :
6Y= 5X+10
Y= 5X-15
Solve Graphically :
6Y= 5X+10
Y= 5X-15
Maths-General
Maths-
Graph the function : g(x)= x2 + 5
Graph the function : g(x)= x2 + 5
Maths-General
Maths-
Graph the function f(x)= (x-2)2
Graph the function f(x)= (x-2)2
Maths-General
Maths-
A man goes 10 m due east and then 30 m in due north. Find the distance from the starting place.
A man goes 10 m due east and then 30 m in due north. Find the distance from the starting place.
Maths-General
Maths-
Graph the function h(x)= -2(x+4)2+1
Graph the function h(x)= -2(x+4)2+1
Maths-General
Maths-
Write a function in vertex form for the parabola shown below :
Write a function in vertex form for the parabola shown below :
Maths-General
Maths-
The height of a ball thrown into the air is a quadratic function of time, the ball is thrown from a height of 6 ft above the ground. After 1 second, the ball reaches its maximum height of 22 ft above the ground, write the equation of the function in vertex form.
The height of a ball thrown into the air is a quadratic function of time, the ball is thrown from a height of 6 ft above the ground. After 1 second, the ball reaches its maximum height of 22 ft above the ground, write the equation of the function in vertex form.
Maths-General
Maths-
Solve Graphically :
X+Y= -1
Y-2X=-4
Solve Graphically :
X+Y= -1
Y-2X=-4
Maths-General
Maths-
Two poles 30m and 15 m high stand upright in a ground. If their feet are 36m apart, find the distance between their tops?
Two poles 30m and 15 m high stand upright in a ground. If their feet are 36m apart, find the distance between their tops?
Maths-General
Maths-
How can you determine the values of h and k from the graph shown? Write the function for the parabola.
How can you determine the values of h and k from the graph shown? Write the function for the parabola.
Maths-General
Maths-
To graph the function f(x)= (x-5)2 -8, a student translates the graph of the quadratic parent function 5 units right and 8 units down. Can a student produce the graph of f(x)= 2(x+3)2 -5 by simply translating the quadratic parent function? Explain
To graph the function f(x)= (x-5)2 -8, a student translates the graph of the quadratic parent function 5 units right and 8 units down. Can a student produce the graph of f(x)= 2(x+3)2 -5 by simply translating the quadratic parent function? Explain
Maths-General
Maths-
The graph shown is a translation of the graph of f(x)=2x2. Write the function for the graph in vertex form
The graph shown is a translation of the graph of f(x)=2x2. Write the function for the graph in vertex form
Maths-General
Maths-
The diagonals of a rhombus are 12 cm and 9 cm long. Calculate the length of one side of a rhombus?
The diagonals of a rhombus are 12 cm and 9 cm long. Calculate the length of one side of a rhombus?
Maths-General
Maths-
The graph of h is the graph of g(x)= (x-2)2+6 translated 5 units left and 3 units down.
a. Describe the graph of h as a translation of the graph of f(x)= x2
b. Write the function h in vertex form.
The graph of h is the graph of g(x)= (x-2)2+6 translated 5 units left and 3 units down.
a. Describe the graph of h as a translation of the graph of f(x)= x2
b. Write the function h in vertex form.
Maths-General
Maths-
In ∆ABC, ∠ABC = 90° AD is the median to BC and CE is the median to AB. If AC = 5 cm and AD = cm, find CE.
In ∆ABC, ∠ABC = 90° AD is the median to BC and CE is the median to AB. If AC = 5 cm and AD = cm, find CE.
Maths-General