Maths-
General
Easy

Question

At a hot air balloon festival. Mohamed's balloon is at an altitude of 40m and rises 10m/min  Dana's balloon is at an altitude of 165m and descends 15m/min.
a) In how many minutes will both balloons be at the same altitude?

hintHint:

given, the initial heights and rate of increment (or)decrement of balloon .

The correct answer is: In 5 mins both balloons will be at same altitude .


    a)Let the time be t at which both balloons have the same height .
    Find the respective heights for each balloon and equate them to find t.
    b) now find height of any balloon at t (as both will be at same height at t)
    Ans :- a)In 5 mins both balloons will be at the same altitude
    b) The altitude will be  90m.
    Explanation :-
    Let the time be t min at which both balloons have the same height .
    a)
    Step 1:-find the respective heights for both balloon
    Mohamed’s balloon is at an altitude of 40 m and rises 10m/min.
    Height of Mohamed’s balloon at time t = 40 m +  10m/min (t min) = 40 + 10t
    Dana’s balloon is at an altitude of 165m and descends 15m/min.
    Height of Dana’s balloon at time t = 165 m - 15m/min (t min) = 165 -15t
    Step 2:- find t by equating both height
    At time t both balloons have same height
    so, 40 plus 10 t equals 165 minus 15 t
    10 t plus 15 t equals 165 minus 40
    25 t equals 125
    therefore t equals 5
    ∴In 5 mins both balloons will be at same altitude .

    The speed unit is the meter per minute, denoted by the symbol [m/min]. For example, 1 meter per minute is 1 m / 60 s. The rate at which the body moves one meter in one minute. A meter per minute is a smaller unit than a meter per second.
    On the clock, there are three hands hours, the minute, and the second hand. The shortest hand of the clock represents the hour, the middle hand represents the minute, and the most extended hand represents the second. Therefore, minutes can be calculated by multiplying the number it points to by five.
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