Question
Richard and teo have a combined age of 31 . Richard is 4 years older than twice teo's age. How old are Richard and teo?
Hint:
let the age of Richard and teo be x and y years respectively.
Using the given conditions frame the system of equation and solve them to get richard and teo ages.
The correct answer is: The age of Richard and teo be 22 and 9 years respectively.
Ans :- The age of richard = x = 22 yrs ;The age of teo = y = 9 yrs
Explanation :-
let the age of Richard and teo be x and y years respectively.
Step 1:- frame the system of linear equations from given conditions.
Richard and teo have a combined age of 31
I.e —Eq1
Richard is 4 years older than twice teo’s age
I.e —Eq2
Step 2:- find y by substituting Eq2 in Eq1.
∴ y = 9
Step 3:- find the value of x by substituting value of y
∴ x = 22
∴The age of Richard and teo be 22 and 9 years respectively.
Tips to help you answer the questions on the problems of age: a.) The age after n years will be (x+n) if you assume that the current age is x.
b.) The age before n years will be (x-n) if you assume the present age to be x.
c.) If the age is expressed as a ratio, p:q, the age will be rounded to the nearest multiple of q and p.
d.) Given that you are assuming you are currently x years old, n times that number equals (xn) years.
E.g.:The father is three times older than Ronit. So he would be 2.5 times Ronit's age after '8' years. How many more times would he be Ronit's age after another '8' years?
A. 2 times
B. 2 1/2 times
C. 2 3/4 times
D. 3 times