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    Chemistry-
    General
    Easy

    Question

    The IUPAC name of given compound is

    1. 2-Ethoxy-4-methoxy pentan-3-one    
    2. 2-Methoxy-4-ethoxy-pentan-3-one    
    3. 2 -Ethoxy-4-methoxy pentan-3-one    
    4. None of these    

    The correct answer is: 2-Ethoxy-4-methoxy pentan-3-one

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    The major product formed in the reaction is

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    In the given reaction

    In the given reaction

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    In the following hydration the major alcohol product formed is -

    In the following hydration the major alcohol product formed is -

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    A tertiary alcohol is obtained when C H subscript 3 end subscript M g I reacts with-

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    ; A&B are given by the set -

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    blank subscript 83 end subscript superscript 214 end superscript B i stack ⟶ with alpha text -emission  end text on top A stack ⟶ with beta text -emission  end text on top B stack ⟶ with beta minus text  cmission  end text on top C stack ⟶ with beta text -emission  end text on top D stack ⟶ with alpha text -emission  end text on top E E' is.an element of stable nucleus What is the element 'E'?

    blank subscript 83 end subscript superscript 214 end superscript B i stack ⟶ with alpha text -emission  end text on top A stack ⟶ with beta text -emission  end text on top B stack ⟶ with beta minus text  cmission  end text on top C stack ⟶ with beta text -emission  end text on top D stack ⟶ with alpha text -emission  end text on top E E' is.an element of stable nucleus What is the element 'E'?

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    Consider the following nuclear reactions: table row cell blank subscript 92 end subscript superscript 238 end superscript M ⟶ blank subscript y end subscript superscript x end superscript N plus 2 blank subscript 2 end subscript superscript 4 end superscript H e end cell row cell blank subscript y end subscript superscript x end superscript N ⟶ blank subscript B end subscript superscript A end superscript L plus 2 beta to the power of plus end exponent end cell end table the number of neutrons present in the element 'L' is:

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