Consider a transformation △ 𝑋𝑌𝑍 →△ 𝐵𝐶𝐷. Understand the order and answer the following questions.
i) What is △ 𝐵𝐶𝐷 called?
ii) What is the relation between the vertices 𝑋, 𝑌, 𝑍 and 𝐵, 𝐶, 𝐷 ?

Solve: $fraction numerator 5 over denominator x plus y end fraction minus fraction numerator 2 over denominator x minus y end fraction equals negative 1$ and $fraction numerator 15 over denominator x plus y end fraction plus fraction numerator 7 over denominator x minus y end fraction equals 10$

Solve the pair of linear equations, $x minus y equals 2 text and end text x plus y equals 2$ Also find p if p = 2x + 3

Solve: $2 x plus y equals 1 semicolon 3 x minus 4 y equals 18$ by using substitution method.

Solve: 3x + y = 8; 5x + y = 10 by using elimination method.

Solve $2 x plus 3 y equals 11$ and $2 x minus 4 y equals negative 24$ by using elimination method.

Solve by using elimination method: $fraction numerator 2 x minus 3 over denominator 4 end fraction minus fraction numerator 2 x minus 1 over denominator 3 end fraction equals 1$

Solve by using elimination method. $fraction numerator 3 x over denominator 5 end fraction minus 2 over 3 equals fraction numerator 2 x over denominator 3 end fraction plus 1 fourth$ .

Solve the following equation by balancing on both sides: b) 6n+7= 3n+25

Solve the following equation by balancing on both sides: a) 5m+9 = 4m + 23

Solve: $fraction numerator 7 x plus 1 over denominator 4 end fraction equals 2 x minus 1$

$table attributes columnspacing 1em end attributes row cell left parenthesis x plus 2 right parenthesis squared plus left parenthesis y minus 3 right parenthesis squared equals 40 end cell row cell y equals negative 2 x plus 4 end cell end table$
Which of the following could be the x-coordinate of a solution to the system of equations above?

Note:
If we had to find the y-coordinate of the system of equations, then we put this value of x in the equation $y equals negative 2 x plus 4$ to get the value of y. Here, we got a quadratic equation of x, which did not have any term containing x, so it was easier to solve. If the quadratic equation was of the form $a x squared plus b c plus c equals 0$ , then we would use the quadratic formula $x equals fraction numerator negative b plus-or-minus square root of b squared minus 4 a c end root over denominator 2 a end fraction$ to solve the equation.

$table attributes columnspacing 1em end attributes row cell left parenthesis x plus 2 right parenthesis squared plus left parenthesis y minus 3 right parenthesis squared equals 40 end cell row cell y equals negative 2 x plus 4 end cell end table$
Which of the following could be the x-coordinate of a solution to the system of equations above?

Solve the equation and check your result 6(3m + 2) – 2(6m – 1) = 3(m – 8) – 6(7m – 6) +9m

Solve and check your answer: 3x – 2(2x – 5) = 2(x + 3) – 8

Solve: 16 = 4 + 3(x + 2)