Question
Find the area of an isosceles trapezium ABCD, if the parallel sides are 6cm and 14 cm, its non parallel sides is 5cm each.
Hint:
Draw the parallel line from C parallel to AD which cuts the AB at E .
We get a triangle and parallelogram. we find the area of triangle in both heron's
method and using formula area = ½ b × h and equating we get height h
Now , find the area of Trapezium = ½ height × (sum of lengths of parallel sides).
The correct answer is: 30 cm2
Ans :- 30 cm2.
Explanation :-
Step 1:- Given lengths of parallel sides is 6 and 14 cm .
Length of non parallel sides is 5 and 5 cm
We get a triangle and parallelogram ABED
we get CE = 5 cm ; AE = 6 cm (opposites sides of parallelogram )
BE = BA-AE = 14- 6 = 8 cm .
Step 2:- Equate the areas and find value of height h
Step 3:-Find the area of trapezium
Therefore, Area of trapezium ABCD = 30 cm2.
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