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Easy

Question

Find the area of an isosceles trapezium ABCD, if the parallel sides are 6cm and 14 cm, its non parallel sides is 5cm each.

hintHint:

Draw the parallel line from C parallel to AD which cuts the AB at E .
We get a triangle and parallelogram. we find the area of triangle in both heron's
method and using formula area = ½ b × h and equating we get height h
Now , find the area of Trapezium =  ½ height × (sum of lengths of parallel sides).

The correct answer is: 30 cm2


    Ans :- 30 cm2.
    Explanation :-
    Step 1:- Given lengths of parallel sides is 6 and 14 cm .
    Length of non parallel sides is 5 and 5 cm
    We get a triangle and parallelogram ABED
    we get CE = 5 cm ; AE = 6 cm (opposites sides of parallelogram )
    BE = BA-AE = 14- 6 = 8 cm .


    Step 2:- Equate the areas and find value of height h
    bold 4 bold italic h equals 12 not stretchy rightwards double arrow bold italic h equals 3 bold italic c bold italic m
    Step 3:-Find the area of trapezium
    text  Areaoftrapezium  end text equals 1 half cross times left parenthesis text  height  end text right parenthesis cross times left parenthesis text  sumoflengthsofparallelsides  end text right parenthesis
    text  Area of trapezium  end text equals 1 half left parenthesis 3 right parenthesis left parenthesis 6 plus 14 right parenthesis equals 3 cross times 10 equals 30 cm squared
    Therefore, Area of trapezium ABCD  =  30 cm2.

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