Question
If 6 • 2k = 36 , what is the value of 4 - 2k ?
- 12
- 10
- 6
- 1
Hint:
Hint:
We are given an equation in one variable and we need to find the value of an expression containing that variable. First, we find the value of k from the given equation and then input the value in 4 - 2k .
To find the value of k , we simplify the equation To simplify 
, we add, subtract, multiply and divide by the same number on both sides.
The correct answer is: 10
Given equation is
Dividing both sides by 6, we get,
Further, dividing by 2 on both sides, we get,
Which gives us
Now, we use this value of k to find the value of the expression 4k -2
We have,
Thus, 
The correct option is B)10
Note:
Here, first we divide by 6 and then again divide by 2. We could also have multiplied 6 and 2 to get 12 and then divide the equation throughout by 12. We can divide both sides by any number except 0. A fraction with 0 as denominator is not defined.
Related Questions to study
I) Is every triangle congruent to itself? Explain why or why not.
I) Is every triangle congruent to itself? Explain why or why not.
A point (x, y) gets translated to the image (9,17) under translation ((𝑥, 𝑦) → (𝑥 − 2, 𝑦 − 1). Find the coordinates of the original point.
A point (x, y) gets translated to the image (9,17) under translation ((𝑥, 𝑦) → (𝑥 − 2, 𝑦 − 1). Find the coordinates of the original point.
If (-2, -9) translates to (-9, 2), then (-5, -1) translates to
If (-2, -9) translates to (-9, 2), then (-5, -1) translates to
Segments OA and OB are radii of the semicircle above. Arc AB has length 3π and OA = 5. What is the value of x ?
A semicircle is formed when a lining passing through the center touches the circle's two ends. As a result of joining two semicircles, we get a circular shape.
A circle is a collection of points equidistant from the circle's center. A radius is a common distance between the center of a circle and its point.
¶Area of a semicircle = 1/2 (π r2)
where r is the radius.
The value is 3.14 or 22/7.
¶Semi circle Formula
¶
| Area | ¶(πr2)/2 | ¶
| Perimeter (Circumference) | ¶(½)πd + d; when diameter (d) is known πr + 2r | ¶
| Angle in a semicircle | ¶¶90 degrees, i.e., right angle ¶ | ¶
| Central angle | ¶180 degrees | ¶
Segments OA and OB are radii of the semicircle above. Arc AB has length 3π and OA = 5. What is the value of x ?
A semicircle is formed when a lining passing through the center touches the circle's two ends. As a result of joining two semicircles, we get a circular shape.
A circle is a collection of points equidistant from the circle's center. A radius is a common distance between the center of a circle and its point.
¶Area of a semicircle = 1/2 (π r2)
where r is the radius.
The value is 3.14 or 22/7.
¶Semi circle Formula
¶
| Area | ¶(πr2)/2 | ¶
| Perimeter (Circumference) | ¶(½)πd + d; when diameter (d) is known πr + 2r | ¶
| Angle in a semicircle | ¶¶90 degrees, i.e., right angle ¶ | ¶
| Central angle | ¶180 degrees | ¶
𝐴𝐵 → 𝐶𝐷 is a rotation. Which of the following statements is true?
𝐴𝐵 → 𝐶𝐷 is a rotation. Which of the following statements is true?
In the figure, ABCD is a trapezium with 
. Find the area of trapezium if 
In the figure, ABCD is a trapezium with . Find the area of trapezium if
In △ ABC and △ DEF , ∠A ≅ ∠D, ∠B ≅ ∠E , then ∠C ≅ ?
In △ ABC and △ DEF , ∠A ≅ ∠D, ∠B ≅ ∠E , then ∠C ≅ ?
The table above shows two pairs of values for the linear function f. The function can be written in the form 
, where a and b are constants. What is the value of a + b ?
Note:
We can take a different approach to solving the linear equations. The above method is called method of elimination. We may also use the method of substitution; which is finding the values one variable, say a , in terms of b , from the first equation and replacing this value in the second equation to get a linear equation in one variable , b . Then solve it to find b, and use it in the previous equation to find a.
The table above shows two pairs of values for the linear function f. The function can be written in the form , where a and b are constants. What is the value of a + b ?
Note:
We can take a different approach to solving the linear equations. The above method is called method of elimination. We may also use the method of substitution; which is finding the values one variable, say a , in terms of b , from the first equation and replacing this value in the second equation to get a linear equation in one variable , b . Then solve it to find b, and use it in the previous equation to find a.
Find the value of x.
Find the value of x.
The lengths of two adjacent sides of a parallelogram are respectively 51cm and 37cm. If one of its diagonal is 20cm then find the area of the parallelogram.
The lengths of two adjacent sides of a parallelogram are respectively 51cm and 37cm. If one of its diagonal is 20cm then find the area of the parallelogram.
Find the area of the shaded region. Here ABC is an equilateral triangle of side 14cm and BDC is a semicircle.
Find the area of the shaded region. Here ABC is an equilateral triangle of side 14cm and BDC is a semicircle.
If △ BCD = △ OPQ, △ OPQ ≅ △ TUV , then what is the relation between △ BCD and △
TUV ?
If △ BCD = △ OPQ, △ OPQ ≅ △ TUV , then what is the relation between △ BCD and △
TUV ?
In the complex number system, what is the value of 
? (Note:
Note:
It is advised to memorize the values of powers of i , that is ,
We can observe that 
for all natural number . Also, even powers of is always a real number n, either 1 or - 1
In the complex number system, what is the value of ? (Note:
Note:
It is advised to memorize the values of powers of i , that is ,
We can observe that for all natural number . Also, even powers of is always a real number n, either 1 or - 1
