Maths-
General
Easy

Question

The lengths of two adjacent sides of a parallelogram are respectively 51cm and 37cm. If one of its diagonal is 20cm then find the area of the parallelogram.

hintHint:

area of parallelogram  ABCD = area of Δ ABC + area of Δ ADC
In parallelogram diagonal divide the area in to two equal parts
I.e  area of Δ ABC =  area of Δ ADC.
Find area of area of Δ ABC by heron's formula for finding the area of triangle

The correct answer is: 612 cm2


    Ans :- 612  (in sq.centimeters)
    Explanation :-
    Step 1:- Find the area of Δ ABC from heron's formula
    Here, side length of triangle are 51,37 and 20 cm
    Heron's formula for area of triangle with side length
    a,b,c are Area equals square root of s left parenthesis s minus a right parenthesis left parenthesis s minus b right parenthesis left parenthesis s minus c right parenthesis end root
    Where s = fraction numerator a plus b plus c over denominator 2 end fraction
    Let a = 51;b = 37 ;c = 20  We get s = fraction numerator 51 plus 37 plus 20 over denominator 2 end fraction = 54
    Area of  Δ ADC = square root of 54 left parenthesis 54 minus 51 right parenthesis left parenthesis 54 minus 37 right parenthesis left parenthesis 54 minus 20 right parenthesis end root
    equals square root of 54 cross times 3 cross times 17 cross times 34 end root
    square root of 93636 equals 306 cm squared
    We get the area of Δ ABC = 306 (cm2).
    Step 2:- Find the area of  Δ ADC.
    In parallelogram diagonal divide the area in to two equal parts
    area of Δ ABC =  area of Δ ADC
    area of Δ ADC = 306 (cm2).

    Step 3:- Find the total area of parallelogram
    area of parallelogram  ABCD = area of Δ ABC + area of Δ ADC
    area of parallelogram  ABCD = 306 (cm2)+ 306 (cm2)
    ∴Area of parallelogram  ABCD = 612 (cm2).

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