Maths-
General
Easy

Question

text  If  end text cos left parenthesis theta minus alpha right parenthesis equals a times cos space left parenthesis theta minus beta right parenthesis equals b then s i n squared space left parenthesis alpha minus beta right parenthesis plus 2 a b c o s space left parenthesis alpha minus beta right parenthesis equals

  1. a squared plus b squared
  2. a squared minus b squared
  3. b squared minus a squared
  4. negative a squared minus b squared

The correct answer is: a squared plus b squared

Related Questions to study

General
Maths-

if fraction numerator cos space x minus cos space alpha over denominator cos space x minus cos space beta end fraction equals fraction numerator sin squared begin display style space end style alpha cos space beta over denominator sin squared begin display style space end style beta cos space alpha end fraction text  then  end text cos text end text x equals

if fraction numerator cos space x minus cos space alpha over denominator cos space x minus cos space beta end fraction equals fraction numerator sin squared begin display style space end style alpha cos space beta over denominator sin squared begin display style space end style beta cos space alpha end fraction text  then  end text cos text end text x equals

Maths-General
General
Maths-

Assertion: open vertical bar table row cell cos invisible function application left parenthesis theta plus alpha right parenthesis end cell cell cos invisible function application left parenthesis theta plus beta right parenthesis end cell cell cos invisible function application left parenthesis theta plus gamma right parenthesis end cell row cell sin invisible function application left parenthesis theta plus alpha right parenthesis end cell cell sin invisible function application left parenthesis theta plus beta right parenthesis end cell cell sin invisible function application left parenthesis theta plus gamma right parenthesis end cell row cell sin invisible function application left parenthesis beta minus gamma right parenthesis end cell cell sin invisible function application left parenthesis gamma minus alpha right parenthesis end cell cell sin invisible function application left parenthesis alpha minus beta right parenthesis end cell end table close vertical baris independent of theta
Reason: If f(theta) = c, then f(theta) is independent of theta.

Assertion: open vertical bar table row cell cos invisible function application left parenthesis theta plus alpha right parenthesis end cell cell cos invisible function application left parenthesis theta plus beta right parenthesis end cell cell cos invisible function application left parenthesis theta plus gamma right parenthesis end cell row cell sin invisible function application left parenthesis theta plus alpha right parenthesis end cell cell sin invisible function application left parenthesis theta plus beta right parenthesis end cell cell sin invisible function application left parenthesis theta plus gamma right parenthesis end cell row cell sin invisible function application left parenthesis beta minus gamma right parenthesis end cell cell sin invisible function application left parenthesis gamma minus alpha right parenthesis end cell cell sin invisible function application left parenthesis alpha minus beta right parenthesis end cell end table close vertical baris independent of theta
Reason: If f(theta) = c, then f(theta) is independent of theta.

Maths-General
General
Maths-

Statement-1 : The function f(x) = |x3| is differentiable at x = 0
Statement-2 : at x = 0, f to the power of straight prime(x) = 0

Statement-1 : The function f(x) = |x3| is differentiable at x = 0
Statement-2 : at x = 0, f to the power of straight prime(x) = 0

Maths-General
parallel
General
Maths-

Statement-1 : The function y = sin–1 (cos x) is not differentiable at x equals n pi comma n element of Z is particular at x = pi

Statement-2 : fraction numerator d y over denominator d x end fraction=fraction numerator negative sin invisible function application x over denominator vertical line sin invisible function application x vertical line end fraction so the function is not differentiable at the points where sin x = 0.

Statement-1 : The function y = sin–1 (cos x) is not differentiable at x equals n pi comma n element of Z is particular at x = pi

Statement-2 : fraction numerator d y over denominator d x end fraction=fraction numerator negative sin invisible function application x over denominator vertical line sin invisible function application x vertical line end fraction so the function is not differentiable at the points where sin x = 0.

Maths-General
General
Maths-

Statement-1 : fleft parenthesis x right parenthesis equals x to the power of n end exponent s i n invisible function application open parentheses fraction numerator 1 over denominator x end fraction close parentheses semicolon x not equal to 0 equals 0 semicolon x equals 0 is differentiable for all real values of x (n greater or equal than2)
Statement-2 : For n greater or equal than 2, Right derivative = Left derivative (for all real values of x)

Statement-1 : fleft parenthesis x right parenthesis equals x to the power of n end exponent s i n invisible function application open parentheses fraction numerator 1 over denominator x end fraction close parentheses semicolon x not equal to 0 equals 0 semicolon x equals 0 is differentiable for all real values of x (n greater or equal than2)
Statement-2 : For n greater or equal than 2, Right derivative = Left derivative (for all real values of x)

Maths-General
General
Maths-

Statement-1 : f(x) = cos2x + cos3 open parentheses x plus fraction numerator pi over denominator 3 end fraction close parentheses– cos x cos3 open parentheses x plus fraction numerator pi over denominator 3 end fraction close parenthesesThen f‘(x) = 0
Statement-2 : Derivative of constant function is zero

Statement-1 : f(x) = cos2x + cos3 open parentheses x plus fraction numerator pi over denominator 3 end fraction close parentheses– cos x cos3 open parentheses x plus fraction numerator pi over denominator 3 end fraction close parenthesesThen f‘(x) = 0
Statement-2 : Derivative of constant function is zero

Maths-General
parallel
General
Maths-

Let f and g be real valued functions defined on interval (–1, 1) such that g to the power of ′′ left parenthesis x right parenthesis text  is continuous,  end text g left parenthesis 0 right parenthesis not equal to 0. g to the power of straight prime left parenthesis 0 right parenthesis equals 0 comma g to the power of ′′ left parenthesis 0 right parenthesis not equal to 0 comma straight & f left parenthesis x right parenthesis equals g(x)sin x
Statement-1 : stack l i m with x rightwards arrow 0 below [g(x) cot x –g(0) cosec x] =f to the power of ′′ (0)
Statement-2 : f to the power of straight prime(0) = g (0)

Let f and g be real valued functions defined on interval (–1, 1) such that g to the power of ′′ left parenthesis x right parenthesis text  is continuous,  end text g left parenthesis 0 right parenthesis not equal to 0. g to the power of straight prime left parenthesis 0 right parenthesis equals 0 comma g to the power of ′′ left parenthesis 0 right parenthesis not equal to 0 comma straight & f left parenthesis x right parenthesis equals g(x)sin x
Statement-1 : stack l i m with x rightwards arrow 0 below [g(x) cot x –g(0) cosec x] =f to the power of ′′ (0)
Statement-2 : f to the power of straight prime(0) = g (0)

Maths-General
General
Maths-

Statement-1 : If f(x) =fraction numerator left parenthesis e to the power of k x end exponent minus 1 right parenthesis sin invisible function application blank k x over denominator 4 x to the power of 2 end exponent end fraction (x not equal to 0) and f(0) = 9 is continuous at x = 0 then k = ± 6.
Statement-2 : For continuous function stack l i m with x rightwards arrow 0 belowf(x) = f(0)

Statement-1 : If f(x) =fraction numerator left parenthesis e to the power of k x end exponent minus 1 right parenthesis sin invisible function application blank k x over denominator 4 x to the power of 2 end exponent end fraction (x not equal to 0) and f(0) = 9 is continuous at x = 0 then k = ± 6.
Statement-2 : For continuous function stack l i m with x rightwards arrow 0 belowf(x) = f(0)

Maths-General
General
Maths-

Statement-I : Let f(x) = fraction numerator 1 minus tan invisible function application x over denominator 4 x minus pi end fraction, x not equal to fraction numerator pi over denominator 4 end fraction, xelement ofopen parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses. If f(x) is continuous in open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses, Then f open parentheses fraction numerator pi over denominator 4 end fraction close parentheses = negative fraction numerator 1 over denominator 2 end fraction.
Statement-II : f(x) is continuous at x = a ifstack l i m with x rightwards arrow a below f(x) = f(a)

Statement-I : Let f(x) = fraction numerator 1 minus tan invisible function application x over denominator 4 x minus pi end fraction, x not equal to fraction numerator pi over denominator 4 end fraction, xelement ofopen parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses. If f(x) is continuous in open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses, Then f open parentheses fraction numerator pi over denominator 4 end fraction close parentheses = negative fraction numerator 1 over denominator 2 end fraction.
Statement-II : f(x) is continuous at x = a ifstack l i m with x rightwards arrow a below f(x) = f(a)

Maths-General
parallel
General
Maths-

Statement 1 : f(x) = xn sin open parentheses fraction numerator 1 over denominator x end fraction close parentheses is differentiable for all real values of x (n greater or equal than2).
Statement 2 : For n greater or equal than 2, Right derivative = left derivative (for all real values of x).

Statement 1 : f(x) = xn sin open parentheses fraction numerator 1 over denominator x end fraction close parentheses is differentiable for all real values of x (n greater or equal than2).
Statement 2 : For n greater or equal than 2, Right derivative = left derivative (for all real values of x).

Maths-General
General
Chemistry-

If H22 is mixed with Fe2+, which reaction is more likely:

If H22 is mixed with Fe2+, which reaction is more likely:

Chemistry-General
General
Chemistry-

For the following cell reaction P b open parentheses s close parentheses plus H g subscript 2 end subscript S O subscript 4 end subscript open parentheses s close parentheses P b S O subscript 4 end subscript open parentheses s close parentheses plus 2 H g open parentheses l close parentheses E subscript text cell  end text end subscript superscript ring operator end superscript equals 0.92 V comma K subscript S p end subscript open parentheses P b S O subscript 4 end subscript close parentheses equals 2 cross times 10 to the power of negative 8 end exponent, K subscript S p end subscript open parentheses H g S O subscript 4 end subscript close parentheses equals 1 cross times 10 to the power of negative 6 end exponent Hence, Ecell is:

For the following cell reaction P b open parentheses s close parentheses plus H g subscript 2 end subscript S O subscript 4 end subscript open parentheses s close parentheses P b S O subscript 4 end subscript open parentheses s close parentheses plus 2 H g open parentheses l close parentheses E subscript text cell  end text end subscript superscript ring operator end superscript equals 0.92 V comma K subscript S p end subscript open parentheses P b S O subscript 4 end subscript close parentheses equals 2 cross times 10 to the power of negative 8 end exponent, K subscript S p end subscript open parentheses H g S O subscript 4 end subscript close parentheses equals 1 cross times 10 to the power of negative 6 end exponent Hence, Ecell is:

Chemistry-General
parallel
General
Chemistry-

Extraction of zinc from zinc blende is achieved by-

Extraction of zinc from zinc blende is achieved by-

Chemistry-General
General
Chemistry-

When the sample of Cu with Zn impurity is to be purified by electrolysis, the appropriate electrodes are-
CathodeAnode

When the sample of Cu with Zn impurity is to be purified by electrolysis, the appropriate electrodes are-
CathodeAnode

Chemistry-General
General
Chemistry-

Which statement is not correct for Kohlrausch law?

Which statement is not correct for Kohlrausch law?

Chemistry-General
parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.