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General
Easy

Question

If the LCM of f(x) and g(x) is a to the power of 6 minus b to the power of 6, then their HCF can be ________.

hintHint:

The expansion of the identity, open parentheses a squared minus b squared close parentheses text  is  end text left parenthesis a minus b right parenthesis left parenthesis a plus b right parenthesis.
We are asked to find the possible HCF of the given functions if their LCM is a to the power of 6 minus b to the power of 6.

The correct answer is: the HCF of the functions can be: (a3 - b3) or (a3 + b3)


    Step 1 of 1:
    The given LCM is: a to the power of 6 minus b to the power of 6.
    Prime factorizing it, we have:
    a to the power of 6 minus b to the power of 6 equals open parentheses a cubed close parentheses squared minus open parentheses b cubed close parentheses squared
    equals open parentheses a cubed minus b cubed close parentheses open parentheses a cubed plus b cubed close parentheses
    So, the HCF of the functions can be: open parentheses a cubed minus b cubed close parentheses text  or  end text open parentheses a cubed plus b cubed close parentheses

    LCM × HCF = product of two numbers.

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