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Maths-

General

Easy

Question

$Lt subscript x not stretchy rightwards arrow 0 end subscript space fraction numerator 1 over denominator sin squared begin display style space end style x end fraction minus fraction numerator 1 over denominator sinh squared space x end fraction equals$

$\frac{3}{2}$
0
$\frac{2}{3}$
$\frac{1}{3}$

The correct answer is: $2 over 3$

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The quadratic equation whose roots are I and m where l = $lim for theta not stretchy rightwards arrow 0 of open parentheses fraction numerator 3 sin space theta minus 4 sin cubed space theta over denominator theta end fraction close parentheses m equals lim for theta not stretchy rightwards arrow 0 of open parentheses fraction numerator 2 tan space theta over denominator theta open parentheses 1 minus tan squared space theta close parentheses end fraction close parentheses$ is

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