Maths-
SAT
Easy

Question

C equals 5 over 9 left parenthesis R minus 491.67 right parenthesis
The equation above expresses the temperature C, in degrees Celsius, in terms of the temperature R, in degrees Rankine. Which of the following expresses the temperature in degrees Rankine in terms of the temperature in degrees Celsius?

  1. R equals 9 over 5 C plus 491.67
  2. R equals 9 over 5 C minus 491.67
  3. R equals 5 over 9 C plus 491.67
  4. R equals 5 over 9 C minus 491.67

The correct answer is: R equals 9 over 5 C plus 491.67


    C = 5 over 9(R - 491.67)
    9C = 5(R - 491.67)
    fraction numerator 9 c over denominator 5 end fraction= R - 491.67
    R = fraction numerator 9 c over denominator 5 end fraction  + 491.67.

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