Maths-
SAT
Easy

Question

h(x) = (x - 5)(x + 5)
The function h is defined as shown. For what value of x does the function h reach its minimum value?

  1. -25
  2. -5
  3. 0
  4. 5

The correct answer is: 0


    h(x) = (x – 5) (x + 5)

    = x2 – 25
    The maximum value of ax2 + bx + c will be c = fraction numerator negative b over denominator 2 a end fraction
    Here, a = 1, b = 0, c = -25.

     fraction numerator negative b over denominator 2 a end fraction = 0.

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