Maths-
SAT
Easy

Question

f(x) = x2 + 4x + 4
For the given function f, what is the minimum value of f(x)?

  1. 4
  2. 2
  3. 1
  4. 0

The correct answer is: 0


    f left parenthesis x right parenthesis space equals space x squared plus space 4 x space plus space 4
    The minimum value is located at fraction numerator negative b over denominator 29 end fraction equals fraction numerator negative 4 over denominator 2 left parenthesis 1 right parenthesis end fraction equals fraction numerator negative 4 over denominator 2 end fraction equals negative 2
    x2 + 4x + 4
    (-2)2 + 4 (-2) + 4
    4 - 8 + 4
    8 - 8
    =0.

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