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If A plus B plus C equals 90 to the power of ring operator end exponent then s i n to the power of 2 end exponent invisible function application A plus s i n to the power of 2 end exponent invisible function application B plus s i n to the power of 2 end exponent invisible function application C equals

  1. 1 minus 2 sin invisible function application A sin invisible function application B sin invisible function application C    
  2. 1 plus 2 s i n invisible function application A s i n invisible function application B s i n invisible function application C    
  3. 1 plus 2 c o s invisible function application A c o s invisible function application B c o s invisible function application C    
  4. 1 minus 2 c o s invisible function application A c o s invisible function application B c o s invisible function application C    

The correct answer is: 1 minus 2 sin invisible function application A sin invisible function application B sin invisible function application C

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