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General
Easy

Question

If e to the power of e to the power of x end exponent end exponent equals a subscript 0 end subscript plus a subscript 1 end subscript x plus a subscript 2 end subscript x to the power of 2 end exponent plus horizontal ellipsis, then

  1. a subscript 0 end subscript equals 1    
  2. a subscript o end subscript equals e    
  3. a subscript 0 end subscript equals e to the power of e end exponent    
  4. a subscript 0 end subscript equals e to the power of 2 end exponent    

The correct answer is: a subscript o end subscript equals e


    e to the power of e to the power of x end exponent end exponent equals 1 plus fraction numerator e to the power of x end exponent over denominator 1 factorial end fraction plus fraction numerator e to the power of 2 to the power of x end exponent end exponent over denominator 2 factorial end fraction plus...
    equals 1 plus fraction numerator 1 over denominator 1 factorial end fraction open parentheses 1 plus x plus fraction numerator x to the power of 2 end exponent over denominator 2 factorial end fraction plus... close parentheses plus fraction numerator 1 over denominator 2 factorial end fraction open parentheses 1 plus fraction numerator 2 x over denominator 1 factorial end fraction plus fraction numerator open parentheses 2 x close parentheses to the power of 2 end exponent over denominator 2 factorial end fraction plus... close parentheses plus...
    therefore e to the power of e end exponent to the power of x end exponent equals open parentheses 1 plus fraction numerator 1 over denominator 1 factorial end fraction plus fraction numerator 1 over denominator 2 factorial end fraction plus fraction numerator 1 over denominator 3 factorial end fraction plus... close parentheses plus x open parentheses fraction numerator 1 over denominator 1 factorial end fraction plus fraction numerator 2 over denominator 2 factorial 1 factorial end fraction plus... close parentheses plus...
    therefore blank a subscript 0 end subscript equals e

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