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Question

The sum of series not stretchy sum from n equals 1 to infinity of fraction numerator 2 n over denominator open parentheses 2 n plus 1 close parentheses factorial end fraction is

  1. e    
  2. e to the power of negative 1 end exponent    
  3. 2 e    
  4. None of these    

The correct answer is: e to the power of negative 1 end exponent


    We have, not stretchy sum subscript n equals 1 end subscript superscript infinity end superscript fraction numerator 2 n over denominator open parentheses 2 n plus 1 close parentheses factorial end fraction equals not stretchy sum subscript n equals 1 end subscript superscript infinity end superscript fraction numerator 2 n plus 1 minus 1 over denominator open parentheses 2 n plus 1 close parentheses factorial end fraction
    equals not stretchy sum subscript n equals 1 end subscript superscript infinity end superscript open parentheses fraction numerator 1 over denominator open parentheses 2 n close parentheses factorial end fraction minus fraction numerator 1 over denominator open parentheses 2 n plus 1 close parentheses factorial end fraction close parentheses
    not stretchy sum subscript n equals 1 end subscript superscript infinity end superscript fraction numerator 1 over denominator open parentheses 2 n close parentheses factorial end fraction minus not stretchy sum subscript n equals 1 end subscript superscript infinity end superscript fraction numerator 1 over denominator open parentheses 2 n plus 1 close parentheses factorial end fraction
    equals open square brackets fraction numerator e plus e to the power of negative 1 end exponent over denominator 2 end fraction minus 1 close square brackets minus open square brackets fraction numerator e minus e to the power of negative 1 end exponent over denominator 2 end fraction minus 1 close square brackets equals e to the power of negative 1 end exponent

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