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Question

If $f open parentheses x plus y close parentheses equals f open parentheses x. y close parentheses for all x comma y element of R text end text$ and f(2011)=2010 $text end text$ then f(2012)=

2000
2010
2012
2011

The correct answer is: 2010

$f open parentheses 2012 close parentheses equals f open parentheses 2011 plus 1 close parentheses equals f open parentheses 2011.1 close parentheses equals f open parentheses 2011 close parentheses equals 2010.$

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