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Maths-

General

Easy

Question

If the matrix A = $open square brackets table row 8 cell – 6 end cell 2 row cell – 6 end cell 7 cell – 4 end cell row 2 cell – 4 end cell lambda end table close square brackets$ is singular, then λ equal to -

– 5
1
3
–1

The correct answer is: 3

A = Singular $rightwards double arrow$ |A| = 0
$open vertical bar table row 8 cell – 6 end cell 2 row cell – 6 end cell 7 cell – 4 end cell row 2 cell – 4 end cell lambda end table close vertical bar$ = 0
$rightwards double arrow$ 8(7λ – 16) + 6(– 6λ + 8) + 2(24 – 14) = 0
$rightwards double arrow$ 56λ –128 –36λ + 48 + 20 = 0
$rightwards double arrow$ 20λ = 60 $rightwards double arrow$ λ = 3

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chemistry-General

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