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Physics-

General

Easy

Question

Light with energy flux $18 w c m to the power of negative 2 end exponent$ is incident on a mirror of size 2cm´2cm normally. The force experienced by it and momentum delivered in one minute are

$0.48 μ N; 28.8 μ {k g m s}^{- 1}$
$48 μ N; 2.88 μ {k g m s}^{- 1}$
$28.8 μ N; 4.8 μ {k g m s}^{- 1}$
$0.24 μ N; 28.8 μ {k g m s}^{- 1}$

The correct answer is: $0.48 mu N semicolon 28.8 mu k g m s to the power of negative 1 end exponent$

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Light with energy flux $36 W m to the power of negative 2 end exponent$ is incident on a circular part of radius 1.4 m of a perfectly black body. The force experienced by the body and the momentum delivered in 10 minutes are

Light with energy flux $36 W m to the power of negative 2 end exponent$ is incident on a circular part of radius 1.4 m of a perfectly black body. The force experienced by the body and the momentum delivered in 10 minutes are

physics-General

In an apparatus, the electric field was found to oscillate with amplitude of 18 V/m. The amplitude of the oscillating magnetic field will be

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In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of $2 cross times 10 to the power of 10 end exponent$ Hz and amplitude 48 V/m The amplitude of oscillating magnetic field will be

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parallel

The velocity of an electromagnetic wave in a medium is $2 cross times 10 to the power of 8 end exponent m S to the power of negative 1 end exponent$ If the relative permeability is 1 the relative permittivity of the medium is $open parentheses C subscript 0 end subscript equals 3 cross times 10 to the power of 8 end exponent m S to the power of negative 1 end exponent close parentheses$

The velocity of an electromagnetic wave in a medium is $2 cross times 10 to the power of 8 end exponent m S to the power of negative 1 end exponent$ If the relative permeability is 1 the relative permittivity of the medium is $open parentheses C subscript 0 end subscript equals 3 cross times 10 to the power of 8 end exponent m S to the power of negative 1 end exponent close parentheses$

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A condenser of capacity 50 p F is connected to an AC supply of 220 V 50 Hz. The rms value of magnetic field at a distance of 5cm from the axis is

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$Lt subscript x not stretchy rightwards arrow 0 end subscript invisible function application x squared space cos invisible function application 2 over x$

$Lt subscript x not stretchy rightwards arrow 0 end subscript invisible function application x squared space cos invisible function application 2 over x$

parallel

$L subscript x not stretchy rightwards arrow d end subscript open parentheses fraction numerator 2 vertical line x vertical line over denominator x end fraction plus x plus 1 close parentheses$

$L subscript x not stretchy rightwards arrow d end subscript open parentheses fraction numerator 2 vertical line x vertical line over denominator x end fraction plus x plus 1 close parentheses$

$L subscript x not stretchy rightwards arrow 0 end subscript fraction numerator 1 minus cos invisible function application m x over denominator 1 minus cos invisible function application n x end fraction comma n not equal to 0$

$L subscript x not stretchy rightwards arrow 0 end subscript fraction numerator 1 minus cos invisible function application m x over denominator 1 minus cos invisible function application n x end fraction comma n not equal to 0$

$Lt subscript x not stretchy rightwards arrow 0 end subscript invisible function application fraction numerator 1 minus cos invisible function application 2 m x over denominator sin squared invisible function application n x end fraction left parenthesis m comma n element of Z right parenthesis$

$Lt subscript x not stretchy rightwards arrow 0 end subscript invisible function application fraction numerator 1 minus cos invisible function application 2 m x over denominator sin squared invisible function application n x end fraction left parenthesis m comma n element of Z right parenthesis$

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$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator x tan invisible function application 2 x minus 2 x tan invisible function application x over denominator left parenthesis 1 minus cos invisible function application 2 x right parenthesis squared end fraction$

$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator x tan invisible function application 2 x minus 2 x tan invisible function application x over denominator left parenthesis 1 minus cos invisible function application 2 x right parenthesis squared end fraction$

$L t subscript x not stretchy rightwards arrow 1 end subscript fraction numerator log subscript e invisible function application open parentheses 1 plus x cubed close parentheses over denominator sin cubed invisible function application x end fraction$

$L t subscript x not stretchy rightwards arrow 1 end subscript fraction numerator log subscript e invisible function application open parentheses 1 plus x cubed close parentheses over denominator sin cubed invisible function application x end fraction$

$Lt subscript x not stretchy rightwards arrow 1 end subscript invisible function application fraction numerator cube root of x minus 1 over denominator x minus 1 end fraction$

$Lt subscript x not stretchy rightwards arrow 1 end subscript invisible function application fraction numerator cube root of x minus 1 over denominator x minus 1 end fraction$

parallel

$L subscript x not stretchy rightwards arrow 0 end subscript fraction numerator 3 to the power of t minus 1 over denominator square root of 1 plus x end root minus 1 end fraction$

$L subscript x not stretchy rightwards arrow 0 end subscript fraction numerator 3 to the power of t minus 1 over denominator square root of 1 plus x end root minus 1 end fraction$

$Lt subscript x not stretchy rightwards arrow 2 end subscript invisible function application fraction numerator open parentheses 2 x squared minus 7 x minus 4 close parentheses over denominator left parenthesis 2 x minus 1 right parenthesis left parenthesis square root of x minus 2 right parenthesis end fraction$

$Lt subscript x not stretchy rightwards arrow 2 end subscript invisible function application fraction numerator open parentheses 2 x squared minus 7 x minus 4 close parentheses over denominator left parenthesis 2 x minus 1 right parenthesis left parenthesis square root of x minus 2 right parenthesis end fraction$

$Lt subscript x not stretchy rightwards arrow 0 end subscript fraction numerator cos a x minus cos b x over denominator x squared end fraction$

$Lt subscript x not stretchy rightwards arrow 0 end subscript fraction numerator cos a x minus cos b x over denominator x squared end fraction$

parallel

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