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Maths-

General

Easy

Question

Shaded region is represented by

$2 x + 5 y \geq 80, x + y \leq 20, x \geq 0, y \leq 0$
$2 x + 5 y \geq 80, x + y \geq 20, x \geq 0, y \geq 0$
$2 x + 5 y \leq 80, x + y \leq 20, x \geq 0, y \geq 0$
$2 x + 5 y \leq 80, x + y \leq 20, x \leq 0, y \leq 0$

The correct answer is: $2 x plus 5 y less or equal than 80 comma x plus y less or equal than 20 comma x greater or equal than 0 comma y greater or equal than 0$

In given all equations, the origin is present in shaded area, answer (c) satisfy this condition.

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By bisection method, the real root of the equation $x to the power of 3 end exponent minus 9 x plus 1 equals 0$ lying between x=2 and x=4 is nearer to

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If

Then

If

Then

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Two balloons A and B are taken at 300 K, maximum capacity of balloon A and balloon B are 800 ml and 1800 ml respectively. When the balloon system is heated, which one will burst first ? A B 1600 ML 700ML

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chemistry-General

$text If end text P equals open parentheses fraction numerator 1 over denominator x subscript p end subscript end fraction comma p close parentheses semicolon Q equals open parentheses fraction numerator 1 over denominator x subscript q end subscript end fraction comma q close parentheses semicolon R equals open parentheses fraction numerator 1 over denominator x subscript r end subscript end fraction comma r close parentheses blank text where end text x subscript k end subscript not equal to 0 text , dentoes the end text k to the power of text sh end text end exponent$ terms of H.P. for k N $element of$ ,then

$text If end text P equals open parentheses fraction numerator 1 over denominator x subscript p end subscript end fraction comma p close parentheses semicolon Q equals open parentheses fraction numerator 1 over denominator x subscript q end subscript end fraction comma q close parentheses semicolon R equals open parentheses fraction numerator 1 over denominator x subscript r end subscript end fraction comma r close parentheses blank text where end text x subscript k end subscript not equal to 0 text , dentoes the end text k to the power of text sh end text end exponent$ terms of H.P. for k N $element of$ ,then

parallel

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