Maths-
General
Easy

Question

Tangent is drawn to ellipse fraction numerator x to the power of 2 end exponent over denominator 27 end fraction plus y to the power of 2 end exponent equals 1 at left parenthesis 3 square root of 3 cos invisible function application theta comma sin invisible function application theta right parenthesis open parentheses w h e r e theta element of open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses close parentheses. Then the value of theta such that sum of intercepts on axes made by this tangent is minimum, is

  1. fraction numerator pi over denominator 3 end fraction    
  2. fraction numerator pi over denominator 6 end fraction    
  3. fraction numerator pi over denominator 8 end fraction    
  4. fraction numerator pi over denominator 4 end fraction    

The correct answer is: fraction numerator pi over denominator 6 end fraction


    The equation of tangent at given theta point is
    fraction numerator x.3 square root of 3 cos invisible function application theta over denominator 27 end fraction plus fraction numerator y. sin invisible function application theta over denominator 1 end fraction equals 1
    fraction numerator x over denominator 3 square root of 3 sec invisible function application theta end fraction plus fraction numerator y over denominator cosec invisible function application theta end fraction equals 1
    rightwards double arrow Sum of the intercepts on axes is given by
    rightwards double arrow times S equals 3 square root of 3 sec invisible function application theta plus cosec invisible function application theta semicolon theta element of open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses
    fraction numerator d S over denominator d theta end fraction equals 3 square root of 3 s e c invisible function application theta times t a n invisible function application theta minus c o s e c invisible function application theta times c o t invisible function application theta equals 0
    rightwards double arrow tan to the power of 3 end exponent invisible function application theta equals fraction numerator 1 over denominator 3 square root of 3 end fraction rightwards double arrowtan invisible function application theta equals fraction numerator 1 over denominator square root of 3 end fraction
    rightwards double arrow theta equals fraction numerator pi over denominator 6 end fraction

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