Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

The solution of the differential equation $x fraction numerator d to the power of 2 end exponent y over denominator d x to the power of 2 end exponent end fraction equals 1$ , given that $y equals 1 comma fraction numerator d y over denominator d x end fraction equals 0$ when $x equals 1$ , is

$y = x \log x + x + 2$
$y = x \log x - x + 2$
$y = x \log x + x$
$y = x \log x - x$

The correct answer is: $y equals x log invisible function application x minus x plus 2$

$x fraction numerator d to the power of 2 end exponent y over denominator d x to the power of 2 end exponent end fraction equals 1$ Þ $fraction numerator d to the power of 2 end exponent y over denominator d x to the power of 2 end exponent end fraction equals fraction numerator 1 over denominator x end fraction$ Þ $fraction numerator d y over denominator d x end fraction equals log invisible function application x plus c subscript 1 end subscript$
Þ $y equals x log invisible function application x minus x plus c subscript 1 end subscript x plus c subscript 2 end subscript$ (on integrating twice)
Given $y equals 1$ and $fraction numerator d y over denominator d x end fraction equals 0$ at $x equals 1$ Þ $c subscript 1 end subscript equals 0$ and $c subscript 2 end subscript equals 2$
Therefore, the required solution is $y equals x log invisible function application x minus x plus 2$ .

Related Questions to study

Solution of $cos invisible function application x fraction numerator d y over denominator d x end fraction plus y sin invisible function application x equals 1$ is

Solution of $cos invisible function application x fraction numerator d y over denominator d x end fraction plus y sin invisible function application x equals 1$ is

Integrating factor of $fraction numerator d y over denominator d x end fraction plus fraction numerator y over denominator x end fraction equals x to the power of 3 end exponent minus 3$ is

Integrating factor of $fraction numerator d y over denominator d x end fraction plus fraction numerator y over denominator x end fraction equals x to the power of 3 end exponent minus 3$ is

Integrating factor of differential equation $cos invisible function application x fraction numerator d y over denominator d x end fraction plus y sin invisible function application x equals 1$ is

Integrating factor of differential equation $cos invisible function application x fraction numerator d y over denominator d x end fraction plus y sin invisible function application x equals 1$ is

parallel

The solution of the differential equation $fraction numerator d y over denominator d x end fraction plus y equals cos invisible function application x$ is

The solution of the differential equation $fraction numerator d y over denominator d x end fraction plus y equals cos invisible function application x$ is

The solution of the differential equation $fraction numerator d y over denominator d x end fraction plus fraction numerator y over denominator x end fraction equals x to the power of 2 end exponent$ is

The solution of the differential equation $fraction numerator d y over denominator d x end fraction plus fraction numerator y over denominator x end fraction equals x to the power of 2 end exponent$ is

Solution of differential equation $fraction numerator d y over denominator d x end fraction equals fraction numerator y minus x over denominator y plus x end fraction$ is

Solution of differential equation $fraction numerator d y over denominator d x end fraction equals fraction numerator y minus x over denominator y plus x end fraction$ is

parallel

The solution of the equation $fraction numerator d y over denominator d x end fraction equals fraction numerator x over denominator 2 y minus x end fraction$ is

The solution of the equation $fraction numerator d y over denominator d x end fraction equals fraction numerator x over denominator 2 y minus x end fraction$ is

The solution of the differential equation $fraction numerator d y over denominator d x end fraction equals fraction numerator x y over denominator x to the power of 2 end exponent plus y to the power of 2 end exponent end fraction$ is

The solution of the differential equation $fraction numerator d y over denominator d x end fraction equals fraction numerator x y over denominator x to the power of 2 end exponent plus y to the power of 2 end exponent end fraction$ is

The solution of the differential equation $x d y minus y d x equals left parenthesis square root of x to the power of 2 end exponent plus y to the power of 2 end exponent right parenthesis end root d x$ is

The solution of the differential equation $x d y minus y d x equals left parenthesis square root of x to the power of 2 end exponent plus y to the power of 2 end exponent right parenthesis end root d x$ is

parallel

The solution of the equation $fraction numerator d y over denominator d x end fraction equals fraction numerator x plus y over denominator x minus y end fraction$ is

The solution of the equation $fraction numerator d y over denominator d x end fraction equals fraction numerator x plus y over denominator x minus y end fraction$ is

The solution of $fraction numerator d y over denominator d x end fraction plus square root of open parentheses fraction numerator 1 minus y to the power of 2 end exponent over denominator 1 minus x to the power of 2 end exponent end fraction close parentheses end root equals 0$ is

The solution of $fraction numerator d y over denominator d x end fraction plus square root of open parentheses fraction numerator 1 minus y to the power of 2 end exponent over denominator 1 minus x to the power of 2 end exponent end fraction close parentheses end root equals 0$ is

Solution of $y d x minus x d y equals x to the power of 2 end exponent y d x$ is

Solution of $y d x minus x d y equals x to the power of 2 end exponent y d x$ is

parallel

Solution of differential equation $fraction numerator d y over denominator d x end fraction equals 2 x y$ is

Solution of differential equation $fraction numerator d y over denominator d x end fraction equals 2 x y$ is

The solution of the differential equation $x left parenthesis e to the power of 2 y end exponent minus 1 right parenthesis d y plus left parenthesis x to the power of 2 end exponent minus 1 right parenthesis e to the power of y end exponent d x equals 0$ is

The solution of the differential equation $x left parenthesis e to the power of 2 y end exponent minus 1 right parenthesis d y plus left parenthesis x to the power of 2 end exponent minus 1 right parenthesis e to the power of y end exponent d x equals 0$ is

The solution of the equation $sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator d y over denominator d x end fraction close parentheses equals x plus y$ is

The solution of the equation $sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator d y over denominator d x end fraction close parentheses equals x plus y$ is

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.