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Question

The value of lambda for which not stretchy integral fraction numerator 4 x to the power of 3 end exponent plus lambda 4 to the power of x end exponent over denominator 4 to the power of x end exponent plus x to the power of 4 end exponent end fraction dx = log (4x + x4) is -

  1. 1    
  2. log e 4    
  3. log 4 e    
  4. 4    

The correct answer is: log e 4


    4x + x4 = t
     (4x3 + 4x ln e4) dx = dt
    not stretchy integral fraction numerator d t over denominator t end fraction = log |t| + c
    table row cell therefore lambda equals log subscript e end subscript invisible function application 4 end cell end table

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