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Chemistry-

General

Easy

Question

$Na subscript 2 straight B subscript 4 straight O subscript 7 times 10 straight H subscript 2 straight O not stretchy rightwards arrow with straight capital delta on top NaBO subscript 2 plus left parenthesis A right parenthesis plus straight H subscript 2 straight O left parenthesis A right parenthesis plus MnO not stretchy rightwards arrow with straight capital delta on top left parenthesis B right parenthesis$ (A) and (B) are

${Na}_{3} {BO}_{3}, {Mn}_{3} {({BO}_{3})}_{2}$
${Na}_{2} {({BO}_{2})}_{2}, Mn {({BO}_{2})}_{2}$
$B_{2} O_{3}, Mn {({BO}_{2})}_{2}$
None of the above is correct

The correct answer is: $straight B subscript 2 straight O subscript 3 comma Mn open parentheses BO subscript 2 close parentheses subscript 2$

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If $fraction numerator a x over denominator cos invisible function application theta end fraction plus fraction numerator b y over denominator sin invisible function application theta end fraction equals open parentheses a squared minus b squared close parentheses$ ,and $fraction numerator a x sin invisible function application theta over denominator cos squared invisible function application theta end fraction minus fraction numerator b y cos invisible function application theta over denominator sin squared invisible function application theta end fraction equals 0$ ,then $left parenthesis a x right parenthesis to the power of 2 divided by 3 end exponent plus left parenthesis b y right parenthesis to the power of 2 divided by 3 end exponent equals$

If $fraction numerator a x over denominator cos invisible function application theta end fraction plus fraction numerator b y over denominator sin invisible function application theta end fraction equals open parentheses a squared minus b squared close parentheses$ ,and $fraction numerator a x sin invisible function application theta over denominator cos squared invisible function application theta end fraction minus fraction numerator b y cos invisible function application theta over denominator sin squared invisible function application theta end fraction equals 0$ ,then $left parenthesis a x right parenthesis to the power of 2 divided by 3 end exponent plus left parenthesis b y right parenthesis to the power of 2 divided by 3 end exponent equals$

If $A plus cos invisible function application B plus cos invisible function application C equals 0$ then $cos invisible function application 3 straight A plus cos invisible function application 3 straight B plus cos invisible function application 3 straight C$

If $A plus cos invisible function application B plus cos invisible function application C equals 0$ then $cos invisible function application 3 straight A plus cos invisible function application 3 straight B plus cos invisible function application 3 straight C$

The value of $fraction numerator 3 plus cot invisible function application 76 to the power of ring operator cot invisible function application 16 to the power of ring operator over denominator cot invisible function application 76 to the power of ring operator plus cot invisible function application 16 to the power of ring operator end fraction$ is

The value of $fraction numerator 3 plus cot invisible function application 76 to the power of ring operator cot invisible function application 16 to the power of ring operator over denominator cot invisible function application 76 to the power of ring operator plus cot invisible function application 16 to the power of ring operator end fraction$ is

parallel

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If are four angles then $sin invisible function application left parenthesis A minus B right parenthesis times cos invisible function application left parenthesis A plus B right parenthesis plus sin invisible function application left parenthesis B minus C right parenthesis cos invisible function application left parenthesis B plus C right parenthesis plus sin invisible function application left parenthesis C minus D right parenthesis$ . $cos invisible function application left parenthesis C plus D right parenthesis plus sin invisible function application left parenthesis D minus A right parenthesis times cos invisible function application left parenthesis D plus A right parenthesis equals$

If $tan space theta subscript 1 comma tan space theta subscript 2 comma tan space theta subscript 3$ and $tan space theta subscript 4$ are the roots of the equation $x to the power of 4 minus x cubed sin space 2 beta plus x squared cos space 2 beta minus x cos space beta minus sin space beta equals 0$ then $tan space open parentheses theta subscript 1 plus theta subscript 2 plus theta subscript 3 plus theta subscript 4 close parentheses$ is equal to

If $tan space theta subscript 1 comma tan space theta subscript 2 comma tan space theta subscript 3$ and $tan space theta subscript 4$ are the roots of the equation $x to the power of 4 minus x cubed sin space 2 beta plus x squared cos space 2 beta minus x cos space beta minus sin space beta equals 0$ then $tan space open parentheses theta subscript 1 plus theta subscript 2 plus theta subscript 3 plus theta subscript 4 close parentheses$ is equal to

Formula of the following silicate anion is

Formula of the following silicate anion is

chemistry-General

parallel

Sulphide mineral + $CN to the power of minus rightwards arrow with straight O subscript 2 on top open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus 2 open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus plus Zn not stretchy rightwards arrow open square brackets Zn left parenthesis CN right parenthesis subscript 4 close square brackets to the power of 2 minus end exponent plus 2 M$ M
can be

Sulphide mineral + $CN to the power of minus rightwards arrow with straight O subscript 2 on top open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus 2 open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus plus Zn not stretchy rightwards arrow open square brackets Zn left parenthesis CN right parenthesis subscript 4 close square brackets to the power of 2 minus end exponent plus 2 M$ M
can be

chemistry-General

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The value of $cos space y cos space left parenthesis pi divided by 2 minus x right parenthesis minus cos space left parenthesis pi divided by 2 minus y right parenthesis cos space x plus sin space y cos space left parenthesis pi divided by 2 minus x right parenthesis plus cos space x sin space left parenthesis pi divided by 2 minus y right parenthesis$ is Zero if

The value of $cos space y cos space left parenthesis pi divided by 2 minus x right parenthesis minus cos space left parenthesis pi divided by 2 minus y right parenthesis cos space x plus sin space y cos space left parenthesis pi divided by 2 minus x right parenthesis plus cos space x sin space left parenthesis pi divided by 2 minus y right parenthesis$ is Zero if

parallel

If $sin space pi over 18 sin space fraction numerator 5 pi over denominator 18 end fraction sin space fraction numerator 7 pi over denominator 18 end fraction$ =

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parallel

If $theta equals pi over 2 to the power of n plus 1 end exponent$ then $cos space theta cos space 2 theta cos space 2 squared theta horizontal ellipsis cos space 2 to the power of n minus 1 end exponent theta$ is equal to

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parallel

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