Physics-
General
Easy
Question
A charged particle q is shot towards another charged particle Q which is fixed, with a speed v. It approaches Q upto a closest distance
and then returns. If
was given a speed
, the closest distance of approach would be

The correct answer is: 
Let a particle of change
having velocity v approaches Q upto a closest distance
and if the velocity becomes
, the closest distance will be
.’
The law of conservation of energy yields,
Kinetic energy of particle=electric potential energy between them at closest distance of approach.
Or 
Or
(i)

and
(ii)
Dividing Eq. (i) by Eq.(ii),
=


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