Physics-
General
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Question

A nucleus of an element  84 to the power of straight X to the power of 202 end exponent emits an  alpha-particle first, a  beta-particle next and then a gamma photon. The final nucleus formed has an atomic number

  1. 200    
  2. 199    
  3. 83    
  4. 198    

The correct answer is: 83


    84 to the power of straight X to the power of 202 end exponent not stretchy ⟶ with alpha text -decay  end text on top 82 to the power of straight Y to the power of 198 end exponent plus subscript 2 He to the power of 4 and  82 to the power of straight Y to the power of 198 end exponent not stretchy ⟶ with beta text -decay  end text on top 83 to the power of straight Z to the power of 198 end exponent plus subscript negative 1 end subscript beta to the power of 0

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