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Physics-

General

Easy

Question

A particle starts from a point P at a distance of A/2 from the mean position O & travels towards left as shown in the figure. If the time period of SHM, executed about O is T and amplitude A then the equation of motion of particle is :

$x = A s i n (\frac{2 π}{T} t + \frac{π}{6})$
$x = A s i n (\frac{2 π}{T} t + \frac{5 π}{6})$
$x = A c o s (\frac{2 π}{T} t + \frac{π}{6})$
$x = A c o s (\frac{2 π}{T} t + \frac{π}{3})$

The correct answer is: $x equals A s i n invisible function application open parentheses fraction numerator 2 pi over denominator T end fraction t plus fraction numerator 5 pi over denominator 6 end fraction close parentheses$

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