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Physics-

General

Easy

Question

Find the ratio of time periods of two identical springs if they are first joined in series & then in parallel & a mass m is suspended from them :

4
2
1
3

The correct answer is: 2

Related Questions to study

Let u(x) be a twice differenctiable function defined in $0 less or equal than x less or equal than 1 comma$ holds the relation $u to the power of ´ ´ end exponent left parenthesis x right parenthesis equals e to the power of x end exponent u left parenthesis x right parenthesis text in end text x element of left square bracket 0 , 1 right square bracket. text If end text 0 less than x subscript 0 end subscript less than 1 comma$ then

Let u(x) be a twice differenctiable function defined in $0 less or equal than x less or equal than 1 comma$ holds the relation $u to the power of ´ ´ end exponent left parenthesis x right parenthesis equals e to the power of x end exponent u left parenthesis x right parenthesis text in end text x element of left square bracket 0 , 1 right square bracket. text If end text 0 less than x subscript 0 end subscript less than 1 comma$ then

If $f open parentheses x close parentheses equals fraction numerator x to the power of 2 end exponent minus 1 over denominator x to the power of 2 end exponent plus 1 end fraction comma$ for every real number, then minimum value of f

If $f open parentheses x close parentheses equals fraction numerator x to the power of 2 end exponent minus 1 over denominator x to the power of 2 end exponent plus 1 end fraction comma$ for every real number, then minimum value of f

The maximum value of the function $f left parenthesis x right parenthesis equals fraction numerator left parenthesis 1 plus x right parenthesis to the power of 0.6 end exponent over denominator 1 plus x to the power of 0.6 end exponent end fraction$ in the interval [0, 1] is

The maximum value of the function $f left parenthesis x right parenthesis equals fraction numerator left parenthesis 1 plus x right parenthesis to the power of 0.6 end exponent over denominator 1 plus x to the power of 0.6 end exponent end fraction$ in the interval [0, 1] is

parallel

How many real values of x satisfy the inequaligy $e to the power of x end exponent less or equal than x plus 1$ ?

How many real values of x satisfy the inequaligy $e to the power of x end exponent less or equal than x plus 1$ ?

If f(x) is a differentiable real valued function satisfying $f to the power of ´ ´ end exponent left parenthesis x right parenthesis minus 3 f to the power of ´ end exponent left parenthesis x right parenthesis greater than 3 for all x greater or equal than 0$ and $f to the power of ´ left parenthesis 0 right parenthesis equals negative 1 comma$ then $f left parenthesis x right parenthesis plus x for all x greater than 0$ is

If f(x) is a differentiable real valued function satisfying $f to the power of ´ ´ end exponent left parenthesis x right parenthesis minus 3 f to the power of ´ end exponent left parenthesis x right parenthesis greater than 3 for all x greater or equal than 0$ and $f to the power of ´ left parenthesis 0 right parenthesis equals negative 1 comma$ then $f left parenthesis x right parenthesis plus x for all x greater than 0$ is

If the function $f left parenthesis x right parenthesis equals c o s invisible function application vertical line x vertical line minus 2 a x plus b$ increases along the entire number scale, the range of value of a is given by

If the function $f left parenthesis x right parenthesis equals c o s invisible function application vertical line x vertical line minus 2 a x plus b$ increases along the entire number scale, the range of value of a is given by

parallel

Let $f left parenthesis x right parenthesis equals fraction numerator ln invisible function application x over denominator x end fraction for all x greater than 0 comma$ then
Statement-1: $f open parentheses fraction numerator 5 over denominator 2 end fraction close parentheses greater than f open parentheses fraction numerator 9 over denominator 2 end fraction close parentheses$ because
Statement 2 : $f open parentheses x subscript 1 end subscript close parentheses greater than f open parentheses x subscript 2 end subscript close parentheses for all x subscript 1 end subscript element of open parentheses 2 comma 4 close parentheses text and end text x subscript 2 end subscript element of open parentheses 0 comma 2 close parentheses union open parentheses 4 comma infinity close parentheses$

Let $f left parenthesis x right parenthesis equals fraction numerator ln invisible function application x over denominator x end fraction for all x greater than 0 comma$ then
Statement-1: $f open parentheses fraction numerator 5 over denominator 2 end fraction close parentheses greater than f open parentheses fraction numerator 9 over denominator 2 end fraction close parentheses$ because
Statement 2 : $f open parentheses x subscript 1 end subscript close parentheses greater than f open parentheses x subscript 2 end subscript close parentheses for all x subscript 1 end subscript element of open parentheses 2 comma 4 close parentheses text and end text x subscript 2 end subscript element of open parentheses 0 comma 2 close parentheses union open parentheses 4 comma infinity close parentheses$

If f(x) is a polynomial function such that $f open parentheses x close parentheses f open parentheses fraction numerator 1 over denominator x end fraction close parentheses equals f open parentheses x close parentheses plus f open parentheses fraction numerator 1 over denominator x end fraction close parentheses$ for all non zero real values of x and f(4) = -15 then f(3) + f(-3) =

If f(x) is a polynomial function such that $f open parentheses x close parentheses f open parentheses fraction numerator 1 over denominator x end fraction close parentheses equals f open parentheses x close parentheses plus f open parentheses fraction numerator 1 over denominator x end fraction close parentheses$ for all non zero real values of x and f(4) = -15 then f(3) + f(-3) =

The total number of solutions of $left square bracket x right square bracket to the power of 2 end exponent equals x plus 2 open curly brackets x close curly brackets comma$ where [.] and {.} denote greatest integer function and fractional part, respectively is equal to

The total number of solutions of $left square bracket x right square bracket to the power of 2 end exponent equals x plus 2 open curly brackets x close curly brackets comma$ where [.] and {.} denote greatest integer function and fractional part, respectively is equal to

parallel

Let $f left parenthesis x right parenthesis equals x left square bracket x right square bracket$ where $left square bracket x right square bracket$ denotes the greatest integer smaller than or equal to x. When x is not an integer, what is f’ (x) ?

Let $f left parenthesis x right parenthesis equals x left square bracket x right square bracket$ where $left square bracket x right square bracket$ denotes the greatest integer smaller than or equal to x. When x is not an integer, what is f’ (x) ?

For $x comma y element of R comma f left parenthesis x plus y right parenthesis equals f left parenthesis x right parenthesis f left parenthesis y right parenthesis$ with f(1) = 2 If $stretchy sum from k equals 1 to n of f left parenthesis a plus k right parenthesis equals 480 comma$ then the ordered pair (a, n) is

For $x comma y element of R comma f left parenthesis x plus y right parenthesis equals f left parenthesis x right parenthesis f left parenthesis y right parenthesis$ with f(1) = 2 If $stretchy sum from k equals 1 to n of f left parenthesis a plus k right parenthesis equals 480 comma$ then the ordered pair (a, n) is

Let $f left parenthesis x right parenthesis equals m a x times left curly bracket 1 plus s i n invisible function application x comma 1 minus c o s invisible function application x right curly bracket comma x element of left square bracket 0 comma 2 pi right square bracket$ and $g left parenthesis x right parenthesis equals m a x times left curly bracket 1 comma vertical line x minus 1 vertical line right curly bracket for all x element of R comma$ then

Let $f left parenthesis x right parenthesis equals m a x times left curly bracket 1 plus s i n invisible function application x comma 1 minus c o s invisible function application x right curly bracket comma x element of left square bracket 0 comma 2 pi right square bracket$ and $g left parenthesis x right parenthesis equals m a x times left curly bracket 1 comma vertical line x minus 1 vertical line right curly bracket for all x element of R comma$ then

parallel

If functions $f colon left curly bracket 1 comma 2 comma comma horizontal ellipsis comma n right curly bracket rightwards arrow left curly bracket 1995 comma 1996 right curly bracket$ satisfying $f left parenthesis 1 right parenthesis plus f left parenthesis 2 right parenthesis plus horizontal ellipsis plus f left parenthesis 1996 right parenthesis equals text odd end text$ integer, are formed, then number of such functions can be

If functions $f colon left curly bracket 1 comma 2 comma comma horizontal ellipsis comma n right curly bracket rightwards arrow left curly bracket 1995 comma 1996 right curly bracket$ satisfying $f left parenthesis 1 right parenthesis plus f left parenthesis 2 right parenthesis plus horizontal ellipsis plus f left parenthesis 1996 right parenthesis equals text odd end text$ integer, are formed, then number of such functions can be

Let $f open parentheses x close parentheses equals fraction numerator 2 alpha x over denominator 2 x plus 1 end fraction comma x not equal to negative 1 half$ .Then f(f(x)) = x if α =

Let $f open parentheses x close parentheses equals fraction numerator 2 alpha x over denominator 2 x plus 1 end fraction comma x not equal to negative 1 half$ .Then f(f(x)) = x if α =

A = (1,2,3,4,5), B = (1,2,3,4) and $f colon A @ B$ is a function. Then

A = (1,2,3,4,5), B = (1,2,3,4) and $f colon A @ B$ is a function. Then

parallel

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