Physics-
General
Easy

Question

Acceleration–time graph of a body is shown. The corresponding velocity–time graph of the same body is :

  1.    
  2.    
  3.    
  4.    

The correct answer is:

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The graph of displacement u/s time is,

Its corresponding velocity–time graph will be :

The graph of displacement u/s time is,

Its corresponding velocity–time graph will be :

physics-General
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Figure (i) and (ii) below show the displacement–time graphs of two particles moving along the x–axis. We can say that :
i) 
ii) 

Figure (i) and (ii) below show the displacement–time graphs of two particles moving along the x–axis. We can say that :
i) 
ii) 

physics-General
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The displacement versus time graph for a body moving in a straight line is shown in figure. Which of the following regions represents the motion when no force is acting on the body :

The displacement versus time graph for a body moving in a straight line is shown in figure. Which of the following regions represents the motion when no force is acting on the body :

physics-General
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The displacement of a particle as a function of time is shown in the figure. The figure shows that

The displacement of a particle as a function of time is shown in the figure. The figure shows that

physics-General
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The variation of velocity of a particle with time moving along a straight line is illustrated in the following figure. The distance travelled by the particle in four seconds is :

The variation of velocity of a particle with time moving along a straight line is illustrated in the following figure. The distance travelled by the particle in four seconds is :

Physics-General
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A particle is dropped vertically from rest from a height. The time taken by it to fall through successive distance of 1 m each will then be :

A particle is dropped vertically from rest from a height. The time taken by it to fall through successive distance of 1 m each will then be :

Physics-General
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physics-

A particle starts from rest. Its acceleration (A) versus time (t) is as shown in the figure. The maximum speed of the particle will be :

A particle starts from rest. Its acceleration (A) versus time (t) is as shown in the figure. The maximum speed of the particle will be :

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A boat is moving with velocity of 3 stack i with hat on top plus 4 stack j with hat on top in river and water is moving with a velocity of negative 3 stack i with hat on top minus 4 stack j with hat on top with respect to ground. Relative velocity of boat with respect to water is :

A boat is moving with velocity of 3 stack i with hat on top plus 4 stack j with hat on top in river and water is moving with a velocity of negative 3 stack i with hat on top minus 4 stack j with hat on top with respect to ground. Relative velocity of boat with respect to water is :

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A man is 45 m behind the bus when the bus start accelerating from rest with acceleration 2.5 m/s2 With what minimum velocity should the man start running to catch the bus?

A man is 45 m behind the bus when the bus start accelerating from rest with acceleration 2.5 m/s2 With what minimum velocity should the man start running to catch the bus?

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The position of a particle moving along the x-axis at certain times is given below :

Which of the following describes the motion correctly :

The position of a particle moving along the x-axis at certain times is given below :

Which of the following describes the motion correctly :

physics-General
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For a moving body at any instant of time :

For a moving body at any instant of time :

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The velocity of a body depends on time according to the equation u = 20 + 0.1t2 The body is undergoing:

The velocity of a body depends on time according to the equation u = 20 + 0.1t2 The body is undergoing:

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Maths-

If integral s e c to the power of fraction numerator 4 over denominator 9 end fraction end exponent invisible function application x times c o s invisible function application e to the power of fraction numerator 14 over denominator 9 end fraction end exponent x d x equals a t a n to the power of b end exponent invisible function application x plus c then a+b= ___

If integral s e c to the power of fraction numerator 4 over denominator 9 end fraction end exponent invisible function application x times c o s invisible function application e to the power of fraction numerator 14 over denominator 9 end fraction end exponent x d x equals a t a n to the power of b end exponent invisible function application x plus c then a+b= ___

Maths-General
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The value of constant a>0 such that stretchy integral subscript 0 end subscript superscript a end superscript   open square brackets tan to the power of negative 1 end exponent invisible function application square root of x close square brackets d x equals stretchy integral subscript 0 end subscript superscript a end superscript   open square brackets cot to the power of negative 1 end exponent invisible function application square root of x close square brackets d x where [.] denotes G.I.F is

The value of constant a>0 such that stretchy integral subscript 0 end subscript superscript a end superscript   open square brackets tan to the power of negative 1 end exponent invisible function application square root of x close square brackets d x equals stretchy integral subscript 0 end subscript superscript a end superscript   open square brackets cot to the power of negative 1 end exponent invisible function application square root of x close square brackets d x where [.] denotes G.I.F is

Maths-General
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Let text end text f colon R to the power of plus end exponent rightwards arrow R be a differentiable function with f left parenthesis A right parenthesis equals 3 and satisfying stretchy integral subscript 1 end subscript superscript x y end superscript   f left parenthesis t right parenthesis d t equals y stretchy integral subscript 1 end subscript superscript x end superscript   f left parenthesis t right parenthesis d t plus x stretchy integral subscript 1 end subscript superscript y end superscript   f left parenthesis t right parenthesis d t for all x comma y element of R to the power of plus end exponent comma text then  end text f left parenthesis x right parenthesis equals

Let text end text f colon R to the power of plus end exponent rightwards arrow R be a differentiable function with f left parenthesis A right parenthesis equals 3 and satisfying stretchy integral subscript 1 end subscript superscript x y end superscript   f left parenthesis t right parenthesis d t equals y stretchy integral subscript 1 end subscript superscript x end superscript   f left parenthesis t right parenthesis d t plus x stretchy integral subscript 1 end subscript superscript y end superscript   f left parenthesis t right parenthesis d t for all x comma y element of R to the power of plus end exponent comma text then  end text f left parenthesis x right parenthesis equals

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