Physics-
General
Easy

Question

An inductor (L = 0.03H) and a resistor (R = 0.15 kcapital omega) are connected in series to a battery of 15V EMF in a circuit shown below. The key K subscript 1 end subscript has been kept closed for a long time. Then at t = 0, K subscript 1 end subscript is opened and key K subscript 2 end subscript is closed simultaneously. At t = 1 ms, the current in the circuit will be (e to the power of 5 end exponent =150)

  1. 6.7 mA    
  2. 0.67 mA    
  3. 100 mA    
  4. 67 Ma    

The correct answer is: 0.67 mA


    According to given conditions:
    table row cell i subscript 0 end subscript equals fraction numerator V over denominator R end fraction equals fraction numerator 15 over denominator 0.15 cross times 10 to the power of 3 end exponent end fraction equals 0.1 A end cell row cell i equals i subscript 0 end subscript e to the power of negative fraction numerator R subscript 1 end subscript over denominator L end fraction end exponent end cell row cell equals 0.1 cross times fraction numerator 0.15 d 0 to the power of ´ end exponent cross times 10 to the power of negative 1 end exponent over denominator 0.0 end fraction equals 0.1 cross times e to the power of negative 5 end exponent equals fraction numerator 0.1 over denominator 150 end fraction equals 0.67 m A end cell end table

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