Physics-
General
Easy
Question
In an experiment with a beam balance on unknown mass m is balanced by two known mass m is balanced by two known masses of 16 kg and 4 kg as shown in figure. The value of the unknown mass m is
- 10 kg
- 6 kg
- 8 kg
- 12 kg
The correct answer is: 8 kg
Related Questions to study
physics-
A right triangular plate ABC of mass m is free to rotate in the vertical plane about a fixed horizontal axis through A. It is supported by a string such that the side AB is horizontal. The reaction at the support A is:
A right triangular plate ABC of mass m is free to rotate in the vertical plane about a fixed horizontal axis through A. It is supported by a string such that the side AB is horizontal. The reaction at the support A is:
physics-General
physics-
Two uniform rods of equal length but different masses are rigidly joined to form an L-shaped body, which is then pivoted as shown. If in equilibrium the body is in the shown configuration, ratio M/m will be:
Two uniform rods of equal length but different masses are rigidly joined to form an L-shaped body, which is then pivoted as shown. If in equilibrium the body is in the shown configuration, ratio M/m will be:
physics-General
physics-
A 5 m long pole of 3 kg mass is placed against a smooth vertical well as shown in the figure. Under equilibrium condition, if the pole makes an angle of 37° with the horizontal, the frictional force between the pole and horizontal surface is
A 5 m long pole of 3 kg mass is placed against a smooth vertical well as shown in the figure. Under equilibrium condition, if the pole makes an angle of 37° with the horizontal, the frictional force between the pole and horizontal surface is
physics-General
physics-
A man can move on a horizontal plank supported symmetrically as shown. The variation of normal reaction on support A with distance x of the man from the end of the plank is best represented by :
A man can move on a horizontal plank supported symmetrically as shown. The variation of normal reaction on support A with distance x of the man from the end of the plank is best represented by :
physics-General
physics-
The figure shows an isosceles triangular plate of mass M and base L. The angle at the apex is 90°. The apex lies at the origin and the base is parallel to X–axis
The moment of inertia of the plate about the y-axis is
The figure shows an isosceles triangular plate of mass M and base L. The angle at the apex is 90°. The apex lies at the origin and the base is parallel to X–axis
The moment of inertia of the plate about the y-axis is
physics-General
physics-
The figure shows an isosceles triangular plate of mass M and base L. The angle at the apex is 90°. The apex lies at the origin and the base is parallel to X–axis
The moment of inertia of the plate about its base parallel to the x-axis is
The figure shows an isosceles triangular plate of mass M and base L. The angle at the apex is 90°. The apex lies at the origin and the base is parallel to X–axis
The moment of inertia of the plate about its base parallel to the x-axis is
physics-General
Physics-
The figure shows an isosceles triangular plate of mass M and base L. The angle at the apex is 90°. The apex lies at the origin and the base is parallel to X–axis
The moment of inertia of the plate about the x-axis is
The figure shows an isosceles triangular plate of mass M and base L. The angle at the apex is 90°. The apex lies at the origin and the base is parallel to X–axis
The moment of inertia of the plate about the x-axis is
Physics-General
physics-
The figure shows an isosceles triangular plate of mass M and base L. The angle at the apex is 90°. The apex lies at the origin and the base is parallel to X–axis
The moment of inertia of the plate about the z-axis is
The figure shows an isosceles triangular plate of mass M and base L. The angle at the apex is 90°. The apex lies at the origin and the base is parallel to X–axis
The moment of inertia of the plate about the z-axis is
physics-General
physics-
The figure shows a uniform rod lying along the x-axis. The locus of all the points lying on the xy-plane, about which the moment of inertia of the rod is same as that about O is
The figure shows a uniform rod lying along the x-axis. The locus of all the points lying on the xy-plane, about which the moment of inertia of the rod is same as that about O is
physics-General
physics-
A square plate of mass M and edge L is shown in figure. The moment of inertia of the plate about the axis in the plane of plate passing through one of its vertex making an angle 15° from horizontal is.
A square plate of mass M and edge L is shown in figure. The moment of inertia of the plate about the axis in the plane of plate passing through one of its vertex making an angle 15° from horizontal is.
physics-General
physics-
Moment of inertia of a semicircular ring of radius R and mass M ; about an axis passing through A and perpendicular to the plane of the paper is
Moment of inertia of a semicircular ring of radius R and mass M ; about an axis passing through A and perpendicular to the plane of the paper is
physics-General
physics-
Moment of inertia of a thin semicircular disc (mass = M & radius = R) about an axis through point O and perpendicular to plane of disc, is given by :
Moment of inertia of a thin semicircular disc (mass = M & radius = R) about an axis through point O and perpendicular to plane of disc, is given by :
physics-General
physics-
In the triangular sheet given PQ = QR = l. If M is the mass of the sheet. What is the moment of inertial about PR
In the triangular sheet given PQ = QR = l. If M is the mass of the sheet. What is the moment of inertial about PR
physics-General
physics-
The moment of inertia of semicircular plate of radius R and mass M about axis AA’ in its plane passing through its centre is
The moment of inertia of semicircular plate of radius R and mass M about axis AA’ in its plane passing through its centre is
physics-General
Physics-
A thin uniform rod of mass M and length L has its moment of inertia I1 about its perpendicular bisector. The rod is bend in the form of a semicircular arc. Now its moment of inertia through the centre of the semi circular arc and perpendicular to its plane is I2 . The ratio of I1 : I2 will be _______
A thin uniform rod of mass M and length L has its moment of inertia I1 about its perpendicular bisector. The rod is bend in the form of a semicircular arc. Now its moment of inertia through the centre of the semi circular arc and perpendicular to its plane is I2 . The ratio of I1 : I2 will be _______
Physics-General
