Physics-
General
Easy

Question

In the following diagram, the p d across 6V cell is

  1. 6V    
  2. 5.6V    
  3. 8.2V    
  4. 8.4V    

The correct answer is: 8.4V

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The effective resistance between A and B in the given circuit is

The effective resistance between A and B in the given circuit is

physics-General
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In the figure shown, S is a point monochromatic light source of frequency 6 cross times 10 to the power of 14 end exponent H z. M is a concave mirror of radius of curvature 20 cm and L is a thin converging lens of focal length 3.75 cm. AB is the principal axis of M and L

Light reflected from the mirror and refracted from the lens in succession reaches the screen. An interference pattern is obtained on the screen by this arrangement.
If the lens is replaced by another converging lens of focal length fraction numerator 10 over denominator 3 end fraction c m and the lens is shifted towards right by 2.5 cm then-

In the figure shown, S is a point monochromatic light source of frequency 6 cross times 10 to the power of 14 end exponent H z. M is a concave mirror of radius of curvature 20 cm and L is a thin converging lens of focal length 3.75 cm. AB is the principal axis of M and L

Light reflected from the mirror and refracted from the lens in succession reaches the screen. An interference pattern is obtained on the screen by this arrangement.
If the lens is replaced by another converging lens of focal length fraction numerator 10 over denominator 3 end fraction c m and the lens is shifted towards right by 2.5 cm then-

physics-General
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physics-

Consider the optical system shown in figure. The point source of light S is having wavelength equals to l. The light is reaching screen only after reflection. For point P to be 2nd maxima, the value of l would be (D>>d and d>>l)

Consider the optical system shown in figure. The point source of light S is having wavelength equals to l. The light is reaching screen only after reflection. For point P to be 2nd maxima, the value of l would be (D>>d and d>>l)

physics-General
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General
physics-

Statement-1 : A ray is incident from outside on a glass sphere surrounded by air as shown. This ray may suffer total internal reflection at second interface.

Statement 2 : For a ray going from denser to rarer medium, the ray may suffer total internal reflection.

Statement-1 : A ray is incident from outside on a glass sphere surrounded by air as shown. This ray may suffer total internal reflection at second interface.

Statement 2 : For a ray going from denser to rarer medium, the ray may suffer total internal reflection.

physics-General
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Statement-1 : A beam of white light enters the curved surface of a semicircular piece of glass along the normal. The incoming beam is moved clockwise (so that the angle theta increases), such that the beam always enters along the normal to the curved side. Just before the refracted beam disappears, it becomes predominantly red.

Statement-2 : The index of refraction for light at the red end of the visible spectrum is more than at the violet end.

Statement-1 : A beam of white light enters the curved surface of a semicircular piece of glass along the normal. The incoming beam is moved clockwise (so that the angle theta increases), such that the beam always enters along the normal to the curved side. Just before the refracted beam disappears, it becomes predominantly red.

Statement-2 : The index of refraction for light at the red end of the visible spectrum is more than at the violet end.

physics-General
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chemistry-

Statement-1: In octahedral complexes, the three orbitals (dxy, dyz, dzx) are stable and of low energy while the two orbitals open parentheses d subscript x to the power of 2 end exponent minus y to the power of 2 end exponent end subscript d subscript z to the power of 2 end exponent end subscript close parentheses are unstable and have high energy.
Statement-2: In octahedral complexes, the three d-orbitals (dxy, dyz, dzx) experience less repulsion from the ligands while two d-orbitals open parentheses d subscript x to the power of 2 end exponent minus y to the power of 2 end exponent end subscript d subscript z to the power of 2 end exponent end subscript close parentheses experience more repulsion from the ligands due to their shapes.

Statement-1: In octahedral complexes, the three orbitals (dxy, dyz, dzx) are stable and of low energy while the two orbitals open parentheses d subscript x to the power of 2 end exponent minus y to the power of 2 end exponent end subscript d subscript z to the power of 2 end exponent end subscript close parentheses are unstable and have high energy.
Statement-2: In octahedral complexes, the three d-orbitals (dxy, dyz, dzx) experience less repulsion from the ligands while two d-orbitals open parentheses d subscript x to the power of 2 end exponent minus y to the power of 2 end exponent end subscript d subscript z to the power of 2 end exponent end subscript close parentheses experience more repulsion from the ligands due to their shapes.

chemistry-General
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General
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In the figure shown if a parallel beam of white light is incident on the plane of the slits then the distance of the only white spot on the screen from O is :[ assume d much less-than less than D comma lambda less than d]

In the figure shown if a parallel beam of white light is incident on the plane of the slits then the distance of the only white spot on the screen from O is :[ assume d much less-than less than D comma lambda less than d]

physics-General
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In a Young’s double slit experiment the slits S subscript 1 end subscript & S subscript 2 end subscript are illuminated by a parallel beam of light of wavelength 4000 text Å end text, from the medium of refractive index n subscript 1 end subscript = 1.2. A thin film of thickness 1.2mu m and refractive index n = 1.5 is placed infront of S subscript 1 end subscript perpendicular to path of light. The refractive index of medium between plane of slits & screen is n subscript 2 end subscript = 1.4. If the light coming from the film and S subscript 1 end subscript & S subscript 2 end subscript have equal intensities I then intensity at geometrical centre of the screen O is

In a Young’s double slit experiment the slits S subscript 1 end subscript & S subscript 2 end subscript are illuminated by a parallel beam of light of wavelength 4000 text Å end text, from the medium of refractive index n subscript 1 end subscript = 1.2. A thin film of thickness 1.2mu m and refractive index n = 1.5 is placed infront of S subscript 1 end subscript perpendicular to path of light. The refractive index of medium between plane of slits & screen is n subscript 2 end subscript = 1.4. If the light coming from the film and S subscript 1 end subscript & S subscript 2 end subscript have equal intensities I then intensity at geometrical centre of the screen O is

physics-General
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In a YDSE experiment two slits S subscript 1 end subscript and S subscript 2 end subscript have separation of d = 2 mm. The distance of the screen is D=8/5m. Source S starts moving from a very large distance towards S subscript 2 end subscript perpendicular to S subscript 1 end subscript S subscript 2 end subscript as shown in figure. The wavelength of monochromatic light is 500 nm. The number of maximas observed on the screen at point P as the source moves towards S subscript 2 end subscript is

In a YDSE experiment two slits S subscript 1 end subscript and S subscript 2 end subscript have separation of d = 2 mm. The distance of the screen is D=8/5m. Source S starts moving from a very large distance towards S subscript 2 end subscript perpendicular to S subscript 1 end subscript S subscript 2 end subscript as shown in figure. The wavelength of monochromatic light is 500 nm. The number of maximas observed on the screen at point P as the source moves towards S subscript 2 end subscript is

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General
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An electromagnetic wave of wavelength lambda subscript 0 end subscript (in vacuum) passes from P towards Q crossing three different media of refractive index mu, 2mu and 3mu respectively as shown in figure. ϕP and ϕQ be the phase of the wave at points P and Q. Find the phase difference ϕ Q minus ϕ P. [Take : mu =1]

An electromagnetic wave of wavelength lambda subscript 0 end subscript (in vacuum) passes from P towards Q crossing three different media of refractive index mu, 2mu and 3mu respectively as shown in figure. ϕP and ϕQ be the phase of the wave at points P and Q. Find the phase difference ϕ Q minus ϕ P. [Take : mu =1]

physics-General
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All objects referred to the subsequent problems lie on the principle axis.

If light is incident on surface 2 from right then which of the following is true for image formed after a single refraction.

All objects referred to the subsequent problems lie on the principle axis.

If light is incident on surface 2 from right then which of the following is true for image formed after a single refraction.

physics-General
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All objects referred to the subsequent problems lie on the principle axis.

In above question if the object is real, then the final image formed after two refractions :

All objects referred to the subsequent problems lie on the principle axis.

In above question if the object is real, then the final image formed after two refractions :

physics-General
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General
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All objects referred to the subsequent problems lie on the principle axis. If light is incident on surface 1 from left, the image formed after the first refraction is definitely :

All objects referred to the subsequent problems lie on the principle axis. If light is incident on surface 1 from left, the image formed after the first refraction is definitely :

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The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm. A person suffering for eye defects uses spectacles (Eye glass). The function of lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina. The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length 100/3 cm) then number of lens will be +3. For all the calculations required you can use the lens formula and lens maker's formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens Minimum focal length of eye lens of a normal person is

The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm. A person suffering for eye defects uses spectacles (Eye glass). The function of lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina. The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length 100/3 cm) then number of lens will be +3. For all the calculations required you can use the lens formula and lens maker's formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens Minimum focal length of eye lens of a normal person is

physics-General
General
physics-

Figure I given below shows a glass vessel, partially filled with water. A narrow beam of light is incident vertically down into the water and passes straight through. Figure II shows the vessel glass tilted until the angle theta, such that the light is refracted along the lower surface of the glass. If refractive indices of air, water and glass are 1, 4/3 and 1.5 respectively then

Figure I given below shows a glass vessel, partially filled with water. A narrow beam of light is incident vertically down into the water and passes straight through. Figure II shows the vessel glass tilted until the angle theta, such that the light is refracted along the lower surface of the glass. If refractive indices of air, water and glass are 1, 4/3 and 1.5 respectively then

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