Physics-
General
Easy
Question
Statement-1 : A ray is incident from outside on a glass sphere surrounded by air as shown. This ray may suffer total internal reflection at second interface.
Statement 2 : For a ray going from denser to rarer medium, the ray may suffer total internal reflection.
- Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
- Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
- Statement-1 is True, Statement-2 is False
- Statement-1 is False, Statement-2 is True
The correct answer is: Statement-1 is False, Statement-2 is True
From symmetry the ray shall not suffer TIR at second interface, because the angle of incidence at first interface equals to angle of emergence at second interface. Hence statement 1 is false
Related Questions to study
physics-
Statement-1 : A beam of white light enters the curved surface of a semicircular piece of glass along the normal. The incoming beam is moved clockwise (so that the angle 
increases), such that the beam always enters along the normal to the curved side. Just before the refracted beam disappears, it becomes predominantly red.
Statement-2 : The index of refraction for light at the red end of the visible spectrum is more than at the violet end.
Statement-1 : A beam of white light enters the curved surface of a semicircular piece of glass along the normal. The incoming beam is moved clockwise (so that the angle increases), such that the beam always enters along the normal to the curved side. Just before the refracted beam disappears, it becomes predominantly red.
Statement-2 : The index of refraction for light at the red end of the visible spectrum is more than at the violet end.
physics-General
chemistry-
Statement-1: In octahedral complexes, the three orbitals (dxy, dyz, dzx) are stable and of low energy while the two orbitals 
are unstable and have high energy.
Statement-2: In octahedral complexes, the three d-orbitals (dxy, dyz, dzx) experience less repulsion from the ligands while two d-orbitals experience more repulsion from the ligands due to their shapes.
Statement-1: In octahedral complexes, the three orbitals (dxy, dyz, dzx) are stable and of low energy while the two orbitals are unstable and have high energy.
Statement-2: In octahedral complexes, the three d-orbitals (dxy, dyz, dzx) experience less repulsion from the ligands while two d-orbitals experience more repulsion from the ligands due to their shapes.
chemistry-General
physics-
In the figure shown if a parallel beam of white light is incident on the plane of the slits then the distance of the only white spot on the screen from O is :[ assume 
]
In the figure shown if a parallel beam of white light is incident on the plane of the slits then the distance of the only white spot on the screen from O is :[ assume ]
physics-General
physics-
In a Young’s double slit experiment the slits 
are illuminated by a parallel beam of light of wavelength 
, from the medium of refractive index 
= 1.2. A thin film of thickness 1.2
and refractive index n = 1.5 is placed infront of 
perpendicular to path of light. The refractive index of medium between plane of slits & screen is 
= 1.4. If the light coming from the film and have equal intensities I then intensity at geometrical centre of the screen O is
In a Young’s double slit experiment the slits are illuminated by a parallel beam of light of wavelength , from the medium of refractive index = 1.2. A thin film of thickness 1.2 and refractive index n = 1.5 is placed infront of perpendicular to path of light. The refractive index of medium between plane of slits & screen is = 1.4. If the light coming from the film and have equal intensities I then intensity at geometrical centre of the screen O is
physics-General
physics-
In a YDSE experiment two slits and 
have separation of d = 2 mm. The distance of the screen is D=8/5m. Source S starts moving from a very large distance towards perpendicular to 
as shown in figure. The wavelength of monochromatic light is 500 nm. The number of maximas observed on the screen at point P as the source moves towards is
In a YDSE experiment two slits and have separation of d = 2 mm. The distance of the screen is D=8/5m. Source S starts moving from a very large distance towards perpendicular to as shown in figure. The wavelength of monochromatic light is 500 nm. The number of maximas observed on the screen at point P as the source moves towards is
physics-General
physics-
An electromagnetic wave of wavelength 
(in vacuum) passes from P towards Q crossing three different media of refractive index 
, 2 and 3 respectively as shown in figure. 
P and Q be the phase of the wave at points P and Q. Find the phase difference 
. [Take : =1]
An electromagnetic wave of wavelength (in vacuum) passes from P towards Q crossing three different media of refractive index , 2 and 3 respectively as shown in figure. P and Q be the phase of the wave at points P and Q. Find the phase difference . [Take : =1]
physics-General
physics-
All objects referred to the subsequent problems lie on the principle axis.
If light is incident on surface 2 from right then which of the following is true for image formed after a single refraction.
All objects referred to the subsequent problems lie on the principle axis.
If light is incident on surface 2 from right then which of the following is true for image formed after a single refraction.
physics-General
physics-
All objects referred to the subsequent problems lie on the principle axis.
In above question if the object is real, then the final image formed after two refractions :
All objects referred to the subsequent problems lie on the principle axis.
In above question if the object is real, then the final image formed after two refractions :
physics-General
physics-
All objects referred to the subsequent problems lie on the principle axis.
If light is incident on surface 1 from left, the image formed after the first refraction is definitely :
All objects referred to the subsequent problems lie on the principle axis.
If light is incident on surface 1 from left, the image formed after the first refraction is definitely :
physics-General
physics-
The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person
A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm. A person suffering for eye defects uses spectacles (Eye glass). The function of lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina. The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length 100/3 cm) then number of lens will be +3. For all the calculations required you can use the lens formula and lens maker's formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens
Minimum focal length of eye lens of a normal person is
The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person
A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm. A person suffering for eye defects uses spectacles (Eye glass). The function of lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina. The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length 100/3 cm) then number of lens will be +3. For all the calculations required you can use the lens formula and lens maker's formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens
Minimum focal length of eye lens of a normal person is
physics-General
physics-
Figure I given below shows a glass vessel, partially filled with water. A narrow beam of light is incident vertically down into the water and passes straight through. Figure II shows the vessel glass tilted until the angle , such that the light is refracted along the lower surface of the glass. If refractive indices of air, water and glass are 1, 4/3 and 1.5 respectively then
Figure I given below shows a glass vessel, partially filled with water. A narrow beam of light is incident vertically down into the water and passes straight through. Figure II shows the vessel glass tilted until the angle , such that the light is refracted along the lower surface of the glass. If refractive indices of air, water and glass are 1, 4/3 and 1.5 respectively then
physics-General
physics-
An infinitely long rectangular strip is placed on the principal axis of a concave mirror as shown in the figure. One end of the strip coincides with centre of curvature as shown. The height of rectangular strip is very small in comparison to focal length of the mirror. Then the shape of image of strip formed by concave mirror is
An infinitely long rectangular strip is placed on the principal axis of a concave mirror as shown in the figure. One end of the strip coincides with centre of curvature as shown. The height of rectangular strip is very small in comparison to focal length of the mirror. Then the shape of image of strip formed by concave mirror is
physics-General
physics-
The given lens is broken into four parts and rearranged as shown in the figure. If the initial focal length is f then after rearrangement the equivalent focal length is
The given lens is broken into four parts and rearranged as shown in the figure. If the initial focal length is f then after rearrangement the equivalent focal length is
physics-General
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A particle revolves in clockwise direction (as seen from point A) in a circle C of radius 1 cm and completes one revolution in 2 sec. The axis of the circle and the principal axis of the mirror M coincide. Call it AB. The radius of curvature of the mirror is 21 cm. Then the direction of revolution (as seen from A) of the image of the particle and its speed is
A particle revolves in clockwise direction (as seen from point A) in a circle C of radius 1 cm and completes one revolution in 2 sec. The axis of the circle and the principal axis of the mirror M coincide. Call it AB. The radius of curvature of the mirror is 21 cm. Then the direction of revolution (as seen from A) of the image of the particle and its speed is
physics-General
physics-
In the figure shown find the total magnification after two successive reflections first on 
& then on 
In the figure shown find the total magnification after two successive reflections first on & then on
physics-General
