Physics-
General
Easy

Question

The equivalent capacitance between points A a n d B for the combination of capacitors shown in figure, where all capacitances are in microfarad is

  1. 6.0 mu F    
  2. 4.0 mu F    
  3. 2.0 mu F    
  4. 3.0 mu F    

The correct answer is: 6.0 mu F


    all the three capacitors are connected in parallel. Therefore, equivalent capacitance between points A a n d B is
    C subscript e q end subscript equals 3 plus 3 plus 3 equals 9 mu F.

    therefore C to the power of ´ ´ end exponent equals C subscript 2 end subscript plus C subscript 3 end subscript equals 4 mu F
    As C to the power of ´ ´ end exponent a n d blank C subscript 1 end subscriptare in series,
    fraction numerator 1 over denominator C to the power of ´ ´ ´ ´ end exponent end fraction equals fraction numerator 1 over denominator blank to the power of ´ ´ end exponent end fraction plus fraction numerator 1 over denominator C subscript 1 end subscript end fraction equals fraction numerator 1 over denominator 4 end fraction plus fraction numerator 1 over denominator 4 end fraction
    rightwards double arrow blank C to the power of ´ ´ ´ ´ end exponent equals blank 2 blank mu F
    Similarly, C subscript 4 end subscript a n d blank C subscript 5 end subscript are in parallel
    C to the power of ´ ´ ´ ´ ´ ´ end exponent equals blank 6 plus 2 equals 8 blank mu F
    C to the power of ´ ´ ´ ´ ´ ´ end exponent a n d blank C subscript 6 end subscript are in series
    fraction numerator 1 over denominator C ´ ´ ´ ´ ´ ´ end fraction equals fraction numerator 1 over denominator C ´ ´ ´ ´ ´ ´ end fraction plus fraction numerator 1 over denominator C subscript 6 end subscript end fraction equals fraction numerator 1 over denominator 8 end fraction plus fraction numerator 1 over denominator 8 end fraction
    rightwards double arrow blank C to the power of ´ ´ ´ ´ ´ ´ end exponent equals blank equals 4 blank mu F
    Now, C to the power of ´ ´ ´ ´ ´ ´ end exponent a n d blank C ´ ´ ´ ´ are in parallel.
    therefore blank C equals 4 mu F plus 2 mu F equals 6 mu F

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