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Physics-

General

Easy

Question

The total energy stored in the condenser system shown in the figure will be

2 $μ J$
4 $μ J$
8 $μ J$
16 $μ J$

The correct answer is: 8 $mu J$

6 $blank mu F$ and 3 $blank mu F$ capacitors are in series
$fraction numerator 1 over denominator C subscript 1 end subscript end fraction equals fraction numerator 1 over denominator 6 end fraction plus fraction numerator 1 over denominator 3 end fraction$
$C subscript 1 end subscript equals 2$
$C subscript 1 end subscript i s blank p a r a l l e l blank t o blank 2 blank mu F blank c a p a c i t o r$
$therefore blank C subscript e q end subscript equals 2 plus 2 equals 4 mu F blank$
Total energy, $U equals fraction numerator 1 over denominator 2 end fraction C V to the power of 2 end exponent$
$equals fraction numerator 1 over denominator 2 end fraction cross times 4 cross times open parentheses 2 close parentheses to the power of 2 end exponent equals 8 mu J$

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