The figure shows a double slit experiment P and Q are the slits. The path lengths PX and QX are $n lambda$ and $left parenthesis n plus 2 right parenthesis lambda$ respectively, where n is a whole number and $lambda$ is the wavelength. Taking the central fringe as zero, what is formed at X

A particle starts from rest. Its acceleration $open parentheses a close parentheses blank v e r s u s$ time $open parentheses t close parentheses$ is as shown in the figure. The maximum speed of the particle will be

In figure, one car at rest and velocity of the light from head light is $c$ , tehn velocity of light from head light for the moving car at velocity $v$ , would be

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If α and β are two different solutions lying between $fraction numerator negative pi over denominator 2 end fraction$ and of the equation $2 Tan space theta plus Sec space theta equals 2$ then Tan α + Tan β is

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A particle of mass $m$ is initially situated at the point $P$ inside a hemispherical surface of radius $r$ as shown in figure. A horizontal acceleration of magnitude $a subscript 0 end subscript$ is suddenly produced on the particle in the horizontal direction. If gravitational acceleration is neglected, the time taken by particle to touch the sphere again is

A cyclist starts from the centre $O$ of a circular park of radius 1 km, reaches the edge $P$ of the park, then cycles along the circumference and returns to the point $O$ as shown in figure. If the round trip takes 10 min, the net displacement and average speed of the cyclist (in metre and kilometer per hour) are

A the instant a motor bike starts from rest in a given direction, a car overtakes the motor bike, both moving in the same direction. The speed-time graphs for motor bike and car are represented by $O A B$ and $C D$ respectively Then

Assertion : Owls can move freely during night.
Reason : They have large number of rods on their retina.

A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point

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The area bounded by y=3x and $y equals x to the power of 2 end exponent$ is

So now here we can say that using the integration method, the area of the region bounded by the given curves is 4.5. The equation A = ∫ab f(x) dx gives the area under the curve y = f(x) and x-axis. The bounding values for the curve with respect to the x-axis are shown here as a and b.

The area bounded by y=3x and $y equals x to the power of 2 end exponent$ is

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The area bounded by $y equals x squared plus 2 comma$ X- axis, x=1 and x=2 is

So now here we can say that using the integration method, the area of the region bounded by the given curve and the lines is 13/3. The equation A = ∫ab f(x) dx gives the area under the curve y = f(x) and x-axis. The bounding values for the curve with respect to the x-axis are shown here as a and b.

The area bounded by $y equals x squared plus 2 comma$ X- axis, x=1 and x=2 is

Maths-General

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If $Cos space 2 theta times Cos space 3 theta times cos space theta equals 1 fourth text for end text 0 less than theta less than pi$ then $theta$ =

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The $x minus t$ graph shown in the figure represents

For the velocity-time graph shown in figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in all the seven seconds

A particle starts from rest at $t equals 0$ and undergoes an acceleration $a$ in $m s to the power of negative 2 end exponent$ with time $t$ in second which is as shownWhich one of the following plot represents velocity $v$ in $m s to the power of negative 1 end exponent blank v e r s u s$ time $t$ in second?