Physics-
General
Easy

Question

Three points charges are placed at the corners of an equilateral triangle of side L as shown in the figure.

  1. The potential at the centroid of the triangle is not zero.    
  2. The electric field at the centroid of the triangle is zero.    
  3. The dipole moment of the system is square root of 2 q L    
  4. The dipole moment of the system is square root of 3 q L.    

The correct answer is: The dipole moment of the system is square root of 3 q L.

Related Questions to study

General
physics-

In the circuit shown in figure : R subscript 1 end subscript equals 10 capital omega comma L equals fraction numerator square root of 3 over denominator 10 end fraction H comma R subscript 2 end subscript equals 20 capital omega and C equals fraction numerator square root of 3 over denominator 2 end fraction mF. Current in L minus R subscript 1 end subscript circuit is I subscript 1 end subscript in C minus R subscript 2 end subscript circuit is I subscript 2 end subscript and the main current is I Phase different between I subscript 1 end subscript and I subscript 2 end subscript is

In the circuit shown in figure : R subscript 1 end subscript equals 10 capital omega comma L equals fraction numerator square root of 3 over denominator 10 end fraction H comma R subscript 2 end subscript equals 20 capital omega and C equals fraction numerator square root of 3 over denominator 2 end fraction mF. Current in L minus R subscript 1 end subscript circuit is I subscript 1 end subscript in C minus R subscript 2 end subscript circuit is I subscript 2 end subscript and the main current is I Phase different between I subscript 1 end subscript and I subscript 2 end subscript is

physics-General
General
physics-

In the LCR circuit shown in figure

A) current will lead the voltage
B) rms value of current is 20 A
C) power factor of the circuit is fraction numerator 1 over denominator square root of 2 end fraction
D) voltage drop across resistance is 100 V

In the LCR circuit shown in figure

A) current will lead the voltage
B) rms value of current is 20 A
C) power factor of the circuit is fraction numerator 1 over denominator square root of 2 end fraction
D) voltage drop across resistance is 100 V

physics-General
General
physics-

In the circuit shown in fig. If both the lamps L subscript 1 end subscript and L subscript 2 end subscript are identical.

In the circuit shown in fig. If both the lamps L subscript 1 end subscript and L subscript 2 end subscript are identical.

physics-General
parallel
General
physics-

The vector diagram of current and voltage for a circuit is as shown. The components of the circuit will be

The vector diagram of current and voltage for a circuit is as shown. The components of the circuit will be

physics-General
General
physics-

The diagram shows a capacitor C and a resistor R connected in series to an ac source. V subscript 1 end subscript and V subscript 2 end subscript are voltameters and A is an ammeter consider now the following statements
I) Readings in A and V subscript 2 end subscript are always in phase
II) Reading in V subscript 1 end subscript is ahead in phase with reading in V subscript 2 end subscript
III) Readings in A and V subscript 1 end subscript are always in phase which of these statements are/is correct

The diagram shows a capacitor C and a resistor R connected in series to an ac source. V subscript 1 end subscript and V subscript 2 end subscript are voltameters and A is an ammeter consider now the following statements
I) Readings in A and V subscript 2 end subscript are always in phase
II) Reading in V subscript 1 end subscript is ahead in phase with reading in V subscript 2 end subscript
III) Readings in A and V subscript 1 end subscript are always in phase which of these statements are/is correct

physics-General
General
physics-

In the circuit shown in the figure, the ac source gives a voltage V=20cos(2000t). Neglecting source resistance, the voltmeter and ammeter reading will be

In the circuit shown in the figure, the ac source gives a voltage V=20cos(2000t). Neglecting source resistance, the voltmeter and ammeter reading will be

physics-General
parallel
General
physics-

The resonance point in X subscript L end subscript minus f and X subscript C end subscript minus f curves is

The resonance point in X subscript L end subscript minus f and X subscript C end subscript minus f curves is

physics-General
General
physics-

A constant voltage at different frequencies is applied across a capacitance C as shown in the figure. Which of the following graphs

Correctly depicts the variation of current with frequency ?

A constant voltage at different frequencies is applied across a capacitance C as shown in the figure. Which of the following graphs

Correctly depicts the variation of current with frequency ?

physics-General
General
physics-

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

voltage across Q is.

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

voltage across Q is.

physics-General
parallel
General
physics-

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Maximum current through circuit is.

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Maximum current through circuit is.

physics-General
General
physics-

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Impedance of p at this frequency is.

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Impedance of p at this frequency is.

physics-General
General
physics-

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given When power loss through resistor is 50 watt, then angular frequency of applied a.c voltage is

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given When power loss through resistor is 50 watt, then angular frequency of applied a.c voltage is

physics-General
parallel
General
physics-

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given The current in the circuit is

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given The current in the circuit is

physics-General
General
physics-

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L,C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given The value of applied peak voltage is

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L,C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given The value of applied peak voltage is

physics-General
General
physics-

The potential different across a 2H inductor as a function of time is shown in figure. At time t=0, current is zero Current versus time graph across the inductor will be

The potential different across a 2H inductor as a function of time is shown in figure. At time t=0, current is zero Current versus time graph across the inductor will be

physics-General
parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.