Physics-
General
Easy

Question

Two blocks A and B placed over an inclined plane of inclination alpha have masses m and M. The coefficients of friction between bodies and plane are respectively mu subscript 1 end subscript and mu subscript 2 end subscript. Find the minimum value of alpha at which the blocks start moving if mu subscript 1 end subscript greater than mu subscript 2 end subscript.

  1. tan invisible function application alpha equals fraction numerator mu subscript 1 end subscript m plus mu subscript 2 end subscript M over denominator open parentheses M plus m close parentheses end fraction    
  2. sin invisible function application alpha equals fraction numerator mu subscript 1 end subscript m plus mu subscript 2 end subscript M over denominator open parentheses M plus m close parentheses end fraction    
  3. cos invisible function application alpha equals fraction numerator mu subscript 1 end subscript m plus mu subscript 2 end subscript M over denominator open parentheses M plus m close parentheses end fraction    
  4. cot invisible function application alpha equals fraction numerator mu subscript 1 end subscript m plus mu subscript 2 end subscript M over denominator open parentheses M plus m close parentheses end fraction    

The correct answer is: tan invisible function application alpha equals fraction numerator mu subscript 1 end subscript m plus mu subscript 2 end subscript M over denominator open parentheses M plus m close parentheses end fraction

Related Questions to study

General
physics-

The system is pushed by a force F as shown in figure. All surfaces are smooth except between B and C. Friction coefficient between B and C is mu. Minimum value of F to prevent block B from downward slipping is

The system is pushed by a force F as shown in figure. All surfaces are smooth except between B and C. Friction coefficient between B and C is mu. Minimum value of F to prevent block B from downward slipping is

physics-General
General
maths-

Assertion: Consider an ellipse having its focii at A(z­1) and B(z­2) in the argand place. If the eccentricity of the ellipse be 'e' and it is known that origin is an interior point of ellipse, then e element of open parentheses 0 comma fraction numerator stack vertical line with ̶ on top z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction close parentheses.
Reason: If Z subscript 0 end subscript is the point interior to curve open vertical bar z minus z subscript 1 end subscript close vertical bar plus open vertical bar z minus z subscript 2 end subscript close vertical bar equals lambda text  then  end text open vertical bar z subscript 0 end subscript minus z subscript 1 end subscript close vertical bar plus open vertical bar z subscript 0 end subscript minus z subscript 2 end subscript close vertical bar less than lambda

Assertion: Consider an ellipse having its focii at A(z­1) and B(z­2) in the argand place. If the eccentricity of the ellipse be 'e' and it is known that origin is an interior point of ellipse, then e element of open parentheses 0 comma fraction numerator stack vertical line with ̶ on top z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction close parentheses.
Reason: If Z subscript 0 end subscript is the point interior to curve open vertical bar z minus z subscript 1 end subscript close vertical bar plus open vertical bar z minus z subscript 2 end subscript close vertical bar equals lambda text  then  end text open vertical bar z subscript 0 end subscript minus z subscript 1 end subscript close vertical bar plus open vertical bar z subscript 0 end subscript minus z subscript 2 end subscript close vertical bar less than lambda

maths-General
General
physics-

Find the least horizontal force P to start motion of any part of the system of the three blocks resting upon one another as shown in figure. The weight of blocks are A equals 300 N comma B equals 100 N and C equals 200 N. Between A and B, mu equals 0.3. Between B and C, mu equals 0.2. between c and the ground mu equals 0.1

Find the least horizontal force P to start motion of any part of the system of the three blocks resting upon one another as shown in figure. The weight of blocks are A equals 300 N comma B equals 100 N and C equals 200 N. Between A and B, mu equals 0.3. Between B and C, mu equals 0.2. between c and the ground mu equals 0.1

physics-General
parallel
General
physics-

In the figure, the block A of mass m is placed on the block B of mass 2m. The coefficient of friction between A and B as well as that between the floor and B is mu. Both blocks are given the same initial velocity to the right. The acceleration of A with respect to B is

In the figure, the block A of mass m is placed on the block B of mass 2m. The coefficient of friction between A and B as well as that between the floor and B is mu. Both blocks are given the same initial velocity to the right. The acceleration of A with respect to B is

physics-General
General
physics-

A weightless inextensible rope rests on a stationary wedge forming an angle alpha with the horizontal. On end of the rope is fixed to the wall at the point A. When a small load is attached to the rope at the point B, the wedge starts moving to the right with constant acceleration 'a'. What is the acceleration of the load when its is still on the wedge?

A weightless inextensible rope rests on a stationary wedge forming an angle alpha with the horizontal. On end of the rope is fixed to the wall at the point A. When a small load is attached to the rope at the point B, the wedge starts moving to the right with constant acceleration 'a'. What is the acceleration of the load when its is still on the wedge?

physics-General
General
physics-

A block of mass m is given an initial downward velocity v subscript 0 end subscript and left on an inclined plane (coefficient of friction0.7). The block will

A block of mass m is given an initial downward velocity v subscript 0 end subscript and left on an inclined plane (coefficient of friction0.7). The block will

physics-General
parallel
General
physics-

A blocks of mass M is sliding down the plane. Coefficient of static friction is mu subscript s end subscript and kinetic friction is mu subscript k end subscript comma Then friction force acting on the block is

A blocks of mass M is sliding down the plane. Coefficient of static friction is mu subscript s end subscript and kinetic friction is mu subscript k end subscript comma Then friction force acting on the block is

physics-General
General
physics-

A horizontal force F equals 20 N is applied on a block of mass 2 kg placed on rough inclined plane with coefficient of friction mu equals 0.2 as shown, then the acceleration of block is open parentheses tan invisible function application 3 7 degree equals fraction numerator 3 over denominator 4 end fraction comma g equals 10 m divided by s to the power of 2 end exponent close parentheses

A horizontal force F equals 20 N is applied on a block of mass 2 kg placed on rough inclined plane with coefficient of friction mu equals 0.2 as shown, then the acceleration of block is open parentheses tan invisible function application 3 7 degree equals fraction numerator 3 over denominator 4 end fraction comma g equals 10 m divided by s to the power of 2 end exponent close parentheses

physics-General
General
physics-

A weightless string passes through a slit over a pulley. The slit offers frictional force f to the string. The string carries two weights having masses m subscript 1 end subscript and m subscript 2 end subscript where m subscript 2 end subscript greater than m subscript 1 end subscript. then acceleration of the weights is

A weightless string passes through a slit over a pulley. The slit offers frictional force f to the string. The string carries two weights having masses m subscript 1 end subscript and m subscript 2 end subscript where m subscript 2 end subscript greater than m subscript 1 end subscript. then acceleration of the weights is

physics-General
parallel
General
physics-

Consider the system shown in figure. The wall is smooth, but the surface of blocks A and B in
contact are rough. The friction on B due to A in equilibrium is

Consider the system shown in figure. The wall is smooth, but the surface of blocks A and B in
contact are rough. The friction on B due to A in equilibrium is

physics-General
General
biology

Two genes R and Y located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregation will show

Two genes R and Y located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregation will show

biologyGeneral
General
maths-

Assertion : The locus of the centre of a circle which touches the circles open vertical bar z minus z subscript 1 end subscript close vertical bar equals a and open vertical bar z minus z subscript 2 end subscript close vertical bar equals b externally (z, z subscript 1 end subscript and z subscript 2 end subscript are complex numbers) will be hyperbola
Reason : open vertical bar z minus z subscript 1 end subscript close vertical bar minus open vertical bar z minus z subscript 2 end subscript close vertical bar less than open vertical bar z subscript 2 end subscript minus z subscript 1 end subscript close vertical bar
not stretchy rightwards double arrowz lies on hyperbola

Assertion : The locus of the centre of a circle which touches the circles open vertical bar z minus z subscript 1 end subscript close vertical bar equals a and open vertical bar z minus z subscript 2 end subscript close vertical bar equals b externally (z, z subscript 1 end subscript and z subscript 2 end subscript are complex numbers) will be hyperbola
Reason : open vertical bar z minus z subscript 1 end subscript close vertical bar minus open vertical bar z minus z subscript 2 end subscript close vertical bar less than open vertical bar z subscript 2 end subscript minus z subscript 1 end subscript close vertical bar
not stretchy rightwards double arrowz lies on hyperbola

maths-General
parallel
General
maths-

Assertion : Consider an ellipse having its foci at A(z subscript 1 end subscript) and B(z subscript 2 end subscript) in the Argand plane. If the eccentricity of the ellipse be 'e' and it is known that origin is an interior point of the ellipse then
e element ofopen parentheses negative fraction numerator vertical line z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction comma fraction numerator vertical line z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction close parentheses
Reason : If Z subscript 0 end subscript is the point interior to curve open vertical bar z minus z subscript 1 end subscript close vertical bar plus open vertical bar z minus z subscript 2 end subscript close vertical bar equals lambda rightwards double arrow open vertical bar z subscript 0 end subscript minus z subscript 1 end subscript close vertical bar plus open vertical bar z subscript 0 end subscript minus z subscript 2 end subscript close vertical bar less than lambda

Assertion : Consider an ellipse having its foci at A(z subscript 1 end subscript) and B(z subscript 2 end subscript) in the Argand plane. If the eccentricity of the ellipse be 'e' and it is known that origin is an interior point of the ellipse then
e element ofopen parentheses negative fraction numerator vertical line z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction comma fraction numerator vertical line z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction close parentheses
Reason : If Z subscript 0 end subscript is the point interior to curve open vertical bar z minus z subscript 1 end subscript close vertical bar plus open vertical bar z minus z subscript 2 end subscript close vertical bar equals lambda rightwards double arrow open vertical bar z subscript 0 end subscript minus z subscript 1 end subscript close vertical bar plus open vertical bar z subscript 0 end subscript minus z subscript 2 end subscript close vertical bar less than lambda

maths-General
General
maths-

If alpha and beta are different complex numbers with | beta | = 1, then open vertical bar fraction numerator beta minus alpha over denominator 1 minus stack alpha with ̄ on top beta end fraction close vertical baris equal to

If alpha and beta are different complex numbers with | beta | = 1, then open vertical bar fraction numerator beta minus alpha over denominator 1 minus stack alpha with ̄ on top beta end fraction close vertical baris equal to

maths-General
General
physics-

What is the maximum value of the force F such that the block shown in the arrangement does not move? open parentheses g equals 10 m divided by s to the power of 2 end exponent close parentheses

What is the maximum value of the force F such that the block shown in the arrangement does not move? open parentheses g equals 10 m divided by s to the power of 2 end exponent close parentheses

physics-General
parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.